Answer:
A) Flow depth = 2.46 m, Froude number after jump = 0.464
B) head loss = 0.572 m
C) dissipation ratio = 0.173
Explanation:
Given data :
Velocity before jump ( v1 ) = 7 m/s
flow depth before jump ( y1 ) = 0.8 m
g = 9.81 m/s
Esi = 3.3 m ( calculated )
attached below is a detailed solution of the problem
Answer:
At steady state output will be 2
Explanation:
We have given transfer function 
Input is unit step so 
We know that
, here
, is output
So output 

Taking 12 common from denominator

Now using partial fraction



On comparing coefficient A=4 and B = -2
Putting the values of A and B in Y(S)

Now taking inverse la place

Steady state means t tends to infinite
So output at steady state = 
Answer:
Approaching a problem and finding a solution within given guidelines.
Explanation:
To be a good engineer, you simply need to know how to create a solution to a problem with a given set of restraints or guidelines.
For instance, let's say your boss wants you to build a machine that can automate some trivial task so he can use the worker elsewhere. He wants the machine to be low maintenance and under $40,000.
As an engineer, your first thought should be, let's see what this "trivial task" is, and then after your observation, you should begin to pull upon your experience and resources to build a solution that can be low maintenance and under $40,000.
Put simply, when you approach a problem, consider all aspects of the problem and then build a solution that satisfies all requirements.
Cheers.
Answer:
Distribution factor P = =38.33
V = 7.826 ml
Explanation:
given details:
BOD =230 mg/l
DO inital = 8.0mg/l
DO final = 2.0mg/l
we know
BOD = [DO inital -DO final] * distribution factor
230 = [8 - 2] D.F
Distribution factor P 
Distribution factor P = =38.33
THE RANGE OF WASTE WATER VOLUME IN 300 ml bottle is
distribution factor 

V = 7.826 ml
I really don’t know good luck