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son4ous [18]
3 years ago
13

Write the empirical formula

Chemistry
1 answer:
stira [4]3 years ago
7 0

Answer:

1)  NH_{4}IO_{3}\\2) Pb(IO_{3})_{4} \\3)  NH_{4}(C_{2}H_{3}O_{2})\\4) Pb(C_{2}H_{3}O_{2})_{4}

Explanation:

1) NH_{4}^{+}IO_{3}^{-} ---> NH_{4}IO_{3}\\2) Pb^{4+}(IO_{3}^{-})_{4} --->Pb(IO_{3})_{4} \\3) NH_{4}^{+}(C_{2}H_{3}O_{2})^{-} ---> NH_{4}(C_{2}H_{3}O_{2})\\4) Pb^{4+}(C_{2}H_{3}O_{2})^{-} _{4} --->Pb(C_{2}H_{3}O_{2})_{4}

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<h3>Mass of the log</h3>

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5 0
2 years ago
If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?
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The reaction between hydrogen and oxygen to form water is given as:

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Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

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3 years ago
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