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son4ous [18]
3 years ago
13

Write the empirical formula

Chemistry
1 answer:
stira [4]3 years ago
7 0

Answer:

1)  NH_{4}IO_{3}\\2) Pb(IO_{3})_{4} \\3)  NH_{4}(C_{2}H_{3}O_{2})\\4) Pb(C_{2}H_{3}O_{2})_{4}

Explanation:

1) NH_{4}^{+}IO_{3}^{-} ---> NH_{4}IO_{3}\\2) Pb^{4+}(IO_{3}^{-})_{4} --->Pb(IO_{3})_{4} \\3) NH_{4}^{+}(C_{2}H_{3}O_{2})^{-} ---> NH_{4}(C_{2}H_{3}O_{2})\\4) Pb^{4+}(C_{2}H_{3}O_{2})^{-} _{4} --->Pb(C_{2}H_{3}O_{2})_{4}

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Answer:

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Answer:

The answer to your question is below

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Carbon-13                  6                            13 - 6 = 7

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6 0
3 years ago
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Answer:

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