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notka56 [123]
2 years ago
12

how many grams of sodium hydroxide are required to dissolve in 232 g of water to make a 2.88 m solution

Chemistry
1 answer:
Gemiola [76]2 years ago
7 0

Grams of Sodium hydroxide : 26.72 g

<h3>Further explanation</h3>

Molality shows the number of moles dissolved in every 1000 grams of solvent.

m = n. (1000 / p)

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

Can be written :

\tt m=\dfrac{mol~solute}{kg~solvent}

  • mol solute(NaOH)

m=2.88

kg solvent(water)=232 g=0.232 kg

\tt mol~solute=m\times kg~solvent\\\\mol~solute=2.88\times 0.232=0.668

  • mass of NaOH

\tt mass=mol\times MW\\\\mass=0.668\times 40~g/mol=26.72~g

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To know more about Henderson Hasselbalch equation, visit the below link:
brainly.com/question/13651361

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