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harkovskaia [24]
1 year ago
8

- Which of the following is a factor of 5x3 - 135?

Mathematics
2 answers:
Marta_Voda [28]1 year ago
8 0

Answer:

5 (x - 3)( {x}^{2}  + 3x + 9)

Step-by-step explanation:

5 {x}^{3}  - 135 \\  \\  = 5 \{ {x}^{3}  - 27 \}\\  \\  = 5 \{ {x}^{3}  -  {(3)}^{3}  \}\\  \\  = 5 (x - 3)( {(x)}^{2}  + (x)(3) +  {(3)}^{2} )\\  \\  = 5 (x - 3)( {x}^{2}  + 3x + 9)

Aleksandr-060686 [28]1 year ago
5 0

Answer: If the question is asking to find the factor of 5x^3-135 then the answer is:
5(x-3)(x^2+3x+9)

Step-by-step explanation:

First, factor out the common term (x^3-27)

5(x^3-27)

Then, factor (x^3-27)

(x-3)(x^2+3x+3^2)

3^2 = 9

<u>5(x-3)(x^2+3x+9) is the answer.</u>

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If you were to solve the following system by substitution, what would be the best
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To solve the two equations simultaneously using the substitution method we need to rearrange one of the equation to make either 'x' or 'y' the subject. 

We can try in turn rearranging both equations and see which unknown term would have been easier to solve first

Equation 2x+8y=12

Making 'x' the subject
2x=12-8y , dividing each term by 2
x=6-4y⇒ (Option 1)

Making 'y' the subject
8y=12-2x, multiply each term by 8 gives
y= \frac{12}{8} - \frac{2}{8}x⇒ (Option 2)

Equation 3x-8y=11
Making 'x' the subject
3x=11+8y, divide each term by 3
x= \frac{11}{3}+ \frac{8}{3}y ⇒ (Option 3)

Making 'y' the subject
8y=3x-11, divide each term by 8
y= \frac{3}{8}x- \frac{11}{8} ⇒ (Option 4)

From all the possibilities of rearranged term, the most efficient option would have been the first option, from equation 2x+8y=12 with 'x' as the subject, x=6-4y





3 0
3 years ago
Read 2 more answers
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. at the same inst
77julia77 [94]

You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²

At the same time, a truck moving speed o 8.50 m/s passes the car

D=v.t (for the truck)

And d= v.t+1/2.a.t²(for the car)

v.t=1/2.a.t²

t=2.v/a

t=2.8.50 m/s/ 2.70 m/s²

17m/2.70=6.29

This mean that the distance is  

D=v.t=8.50m/s.6.29= 53.465 m/s

The speed of the car is  

Vcar=a.t

2.7m/s2×× 53.65

=144.34


4 0
2 years ago
PLEASE HELP ASAP its in the attachment lol
Advocard [28]

Answer: c. 66

Step-by-step explanation:

Add 76 and 38.

76+38 = 114

Take 180 minus 114

180-114 = 66

8 0
3 years ago
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Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Drove 50 km on 6 L of gasoline. Which proportion would help determine how far she can travel on a full 40 L tank of gasoline?
RoseWind [281]

Answer:

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Step-by-step explanation:

50 : 6 = x : 40

x = 50 * 40 : 6

x = 333.33

--------------------------

check

50 : 6 = 333.33 : 40

8.33 = 8.33

The answer is good






3 0
3 years ago
Read 2 more answers
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