Answer:
Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Step-by-step explanation:
Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:
6000 + 3B + B = 24000
3B + B = 24000 - 6000
4B = 18000
B = 18000/4
B = 4500
S = 6000 + 3x4500
S = 6000 + 13500
S = 19500
Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
x ≤ 6
which is A
or if not then it's B for
x ≥ 6
Answer:
Step-by-step explanation:
n and d are the number of nickels and dimes, respectively.
"there are 20 coins"
n+d = 20
d = 20-n
"total value is $1.40"
0.05n + 0.10d = 1.40
0.05n + 0.10(20-n) = 1.40
-0.05n + 2 = 1.40
0.05n = 0.6
n = 12
d = 20-m = 8
Formula for compound interest is
Interest = Amount - Principal
Interest = 
- P
Where r = rate in percent
t = time in years
For Jaina,
P = $300
r= 7%
t = 3 yrs
So, Interest = 
- 300
For Tomas
P = $400
r= 4%
t = 3 yrs
So, Interest = 
- 400
So pair of equations for Jaina and Tomas are
Interest = - 300
Interest = - 400
