To solve the two equations simultaneously using the substitution method we need to rearrange one of the equation to make either

or

the subject.
We can try in turn rearranging both equations and see which unknown term would have been easier to solve first
Equation

Making

the subject

, dividing each term by 2

⇒ (Option 1)
Making

the subject

, multiply each term by 8 gives

⇒ (Option 2)
Equation

Making

the subject

, divide each term by 3

⇒ (Option 3)
Making

the subject

, divide each term by 8

⇒ (Option 4)
From all the possibilities of rearranged term, the most efficient option would have been the first option, from equation

with

as the subject,
You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²
At the same time, a truck moving speed o 8.50 m/s passes the car
D=v.t (for the truck)
And d= v.t+1/2.a.t²(for the car)
v.t=1/2.a.t²
t=2.v/a
t=2.8.50 m/s/ 2.70 m/s²
17m/2.70=6.29
This mean that the distance is
D=v.t=8.50m/s.6.29= 53.465 m/s
The speed of the car is
Vcar=a.t
2.7m/s2×× 53.65
=144.34
Answer: c. 66
Step-by-step explanation:
Add 76 and 38.
76+38 = 114
Take 180 minus 114
180-114 = 66
Answer:
are you mutiplying?
Step-by-step explanation:
Answer:
50 : 6 = x : 40 is the proportion
Step-by-step explanation:
50 : 6 = x : 40
x = 50 * 40 : 6
x = 333.33
--------------------------
check
50 : 6 = 333.33 : 40
8.33 = 8.33
The answer is good