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SCORPION-xisa [38]
2 years ago
8

Dental crown: Uranium-234 is used to make dental crowns appear brighter. The alpha decay of uranium-234 produces what isotope?

Chemistry
1 answer:
Ne4ueva [31]2 years ago
8 0

Answer:

Lithium has two naturally occurring isotopes. Lithium-6 has an atomic mass of 6.015 amu. Lithium-7 has an atomic mass of 7.016 amu. The average atomic mass of lithium is 6.941 amu.

Explanation:

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Why don’t we include the mass of an atoms electrons in the atomic mass?
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Because Electrons have a negative charge

8 0
3 years ago
Iron 3 oxide and carbon react to form iron and carbon dioxide. Balance the equation.
Oksi-84 [34.3K]

Answer:

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

Explanation:

First of all, you have to translate the words into an equation.

Fe(iii)2O3 + C ==> Fe  + CO2

The easiest way to tackle this is to start with the Oxygens and balance them. They must balance by going to the greatest common factor which is 6. So you multiply the molecule by whatever it takes to get the Oxygens to 6

2 Fe(iii)2O3 + C   ==>     Fe  + 3 CO2

Now work on the irons. There 2 on the left and just 1 on the right. So you need to multiply the iron by 2.

2 Fe(iii)2O3 + C ==> 2 Fe  + 3 CO2

Finally it is the turn of the carbons. There are 3 on the right, so you must make the carbon on the left = 3

2 Fe(iii)2O3 + 3 C ==> 2 Fe  + 3 CO2

And you are done.

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4 years ago
Predict the chemical formula for the ionic compound formed by NH4+ and POsub4exponent3-
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4 0
3 years ago
It takes to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond
Zolol [24]

The given question is incomplete. The complete question is :

It takes 151 kJ/mol to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon. Be sure your answer has the correct number of significant digits.

Answer:  793 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = 151 kJ= 151000 J   (1kJ=1000J)

N= moles = 1 = 6.023\times 10^{23}

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light  = 3\times 10^8m/s

\lambda = wavelength of light  = ?

Putting in the values:

151000J=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{\lambda}

{\lambda}=7.93\times 10^{-7}m=793nm    1m=10^{-9}nm

Thus  the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon is 793 nm

3 0
3 years ago
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