Answer:
The specific heat capacity of the metal is 0.268 J/g°C
Explanation:
Step 1: Data given
Mass of the metal = 151.5 grams
The temperature of the metal = 75.0 °C
Temperature of water = 15.1 °C
The temperature of the water rises to 18.7°C.
The specific heat capacity of water is 4.18 J/°C*g
Step 2: Calculate the specific heat capacity of the metal
heat lost = heat gained
Q = m*c*ΔT
Qmetal = - Qwater
m(metal) * c(metal) * ΔT(metal) = m(water) * c(water) * ΔT(water)
⇒ mass of the metal = 151.5 grams
⇒ c(metal) = TO BE DETERMINED
⇒ΔT( metal) = T2 - T1 = 18.7 °C - 75.0 °C = -56.3 °C
⇒ mass of the water = 151.5 grams
⇒ c(water) = 4.184 J/g°C
⇒ ΔT(water) = 18.7° - 15.1 = 3.6 °C
151.5g * c(metal) * -56.3°C = 151.5g * 4.184 J/g°C * 3.6 °C
c(metal) = 0.268 J/g°C
The specific heat capacity of the metal is 0.268 J/g°C
