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2 years ago

NEED STEP BY STEP WORK HIGH POINTS

Mathematics

2 answers:

vazorg [7]2 years ago

6 0

Answer:

The awnser is 16 times 2

equals 32

Step-by-step explanation:

Fudgin [204]2 years ago

3 0

Perimeter:-

$\\ \rm\bull\rightarrowtail 5x^2+4xy+7xy=5x^2+11xy$

Area:-

$\\ \rm\bull\rightarrowtail \dfrac{1}{2}bh=\dfrac{1}{2}(4xy)(5x^2)=2xy(5x^2)=10x^3y$

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Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5) , / at (- 2, 2) , and X at (4, - 1) , where x >

bazaltina [42]

Answer:

Isosceles triangles have two sides with the same length, and one side that ... Similarly, if two angles of a triangle have equal measure, then the sides ... (2) Set up an equation and solve for x. ... x = 60/2 x = 30. Each base angle of triangle ABC measures 30 degrees. ... In isosceles triangle RST, angle S is the vertex angle.

Step-by-step explanation:

8 0

3 years ago

write an equation in slope intercept form for the line that passes through (4, -4) and is parallel to 3x+4x=2y-9

photoshop1234 [79]

Answer:

$\large\boxed{y=\dfrac{7}{2}x-18}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

Convert the equation of a line 3x + 4x = 2y - 9 to the slope-intercept form:

$3x+4x=2y-9$

$7x=2y-9$ add 9 to both sides

$7x+9=2y$ divide both sides by 2

$\dfrac{7}{2}x+\dfrac{9}{2}=y\to y=\dfrac{7}{2}x+\dfrac{9}{2}$

Parallel lines have the same slope. Therefore we have the equation:

$y=\dfrac{7}{2}x+b$

Put the coordinates of the point (4, -4) to the equation:

$-4=\dfrac{7}{2}(4)+b$

$-4=7(2)+b$

$-4=14+b$ subtract 14 from both sides

$-18=b\to b=-18$

Finally we have the equation:

$y=\dfrac{7}{2}x-18$

8 0

3 years ago

The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in

Elanso [62]

Answer:

0 < t < $\frac{5}{3}$

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = $\frac{20}{12}$

t = $\frac{5}{3}$ days

Therefore, there are two intervals in which the given function is defined

(0, $\frac{5}{3}$ ) and ( $\frac{5}{3}$ , ∞)

For the interval (0, $\frac{5}{3}$ ),

p'(1) = 20 - 12(1) = 20

For the interval ( $\frac{5}{3}$ , ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, $\frac{5}{3}$ ) indicates that the function is increasing.

0 < t < $\frac{5}{3}$

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0

3 years ago

The admissions office of a private university released the following admission data for the preceding academic year: From a pool

lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

$0.4\times 0.4=0.16$

Probability of female entered and subsequently enrolled is given by

$0.4\times 0.45\\\\=0.18$

Number of male entered and subsequently enrolled is given by

$0.16\times 4200\\\\=672$

Number of female entered and subsequently enrolled is given by

$0.18\times 3800\\\\=684$

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

$\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695$

Hence, our required probability is 0.1695.

3 0

3 years ago

Brain test This quiz is to answer guys

defon

A - The trip was 2 hours and 15 minutes which is also 135 minutes.
B - if the delays occurred the actual arrival time would be 11:15

Hope this helps !

8 0

2 years ago