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Troyanec [42]
3 years ago
15

Tari serampang dua belas berasal dari​

Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Berdasarkan sejarahnya, tarian ini lahir dan berkembang di wilayah internal Kesultanan Serdang Bedagai, Deli Sedang, Sumatera Utara. Sebelum menggunakan nama “semudah dua belas”, tarian ini pada awalnya bernama tarian Pulau Sari hasil kreasi orang Melayu asli bernama Sauti pada tahun 1940-an.

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Hi guys, my question is:
guapka [62]

Answer:

See Explanation Below

Explanation:

A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.  

B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5

C) The rate will increase by 4 since you are doubling both you have to multiply them both.

8 0
3 years ago
Which of the following is a change of state?
Step2247 [10]

Answer:

I think C. Hope this Helps!

Explanation:

5 0
3 years ago
When electrons are added to the outermost shell of a carbon atom, it forms
jenyasd209 [6]
I believe it forms an anion that has a larger radius.
3 0
3 years ago
Read 2 more answers
What is the solubility of silver chromate in parts per million?
pantera1 [17]
What is the solubility of barium chromate in parts per million?
*parts per million = Grams of Solute/grams of solution X 10^6 (which is ppm)
2.787 x 10^-3g/L x 1L/1000g x 10^6 = 0.02779, or 2.78 x 10^-2ppm

Answer in parts per million to three significant figures =2.78ppm

this is correct for the pearson mastering chemistry question
4 0
3 years ago
Which relationship or statement best describes delta s for the following reaction:
zalisa [80]

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

  • If Δn(g) > 0, the entropy increases (ΔS > 0).
  • If Δn(g) < 0, the entropy decreases (ΔS < 0).
  • If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

4 0
3 years ago
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