When Al(OH)3 and H2SO4 are allowed to react, the products formed are aluminum sulfate (Al2(SO4)3<span> ) and water (H2O). The balanced equation should be written as follows:
</span><span>3H2SO4 + 2Al(OH)3 = Al2(SO4)3 + 6H2O
This reaction is called a neutralization reaction. Hope this answers the question. Have a nice day.</span>
The number of moles hydrogen produced when 6 moles of sodium are used is calculated as below
2Na + 2H2O = 2NaOH +H2
by use of mole ratio between Na to H2 which is 2:1 the moles of H2 is therefore
= 6 x1/2 = 3 moles of H2
The substance that can act as an Arrhenius base in aqueous solution is sodium hydroxide since NaOH dissociates in water giving the sodium ions and the hydroxide ions. An Arrhenius base is a substance that is characterized by forming hydroxide ions in an aqueous solution.
