Question

A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How would the student properly label this solution?
Question 20 options:


2.00 M/L NaCl


116.9 M NaCl


116.9 M NaCl


116.9 g / L NaCl

Answer 1

Answer:

The accurate label for the solution is 2.00 mol/L NaCl.

Explanation:

Molrity = mass ÷ molar mass

Molar mass of NaCL = 58.44 g/mol

Weighed mass = 116.9g

⇒ Molarity of the solution = $\frac{116.9}{68.44}$ = 2.0M

Therefore, the accurate label for the solution is 2.00 mol/L NaCl.