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tamaranim1 [39]
3 years ago
8

A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How

would the student properly label this solution?
Question 20 options:


2.00 M/L NaCl


116.9 M NaCl


116.9 M NaCl


116.9 g / L NaCl
Chemistry
1 answer:
zhenek [66]3 years ago
5 0

Answer:

<em>The accurate label for the solution is</em><em> </em><u><em>2.00 mol/L NaCl.</em></u>

Explanation:

Molrity = mass ÷ molar mass

Molar mass of NaCL = 58.44 g/mol

Weighed mass = 116.9g

⇒ Molarity of the solution = \frac{116.9}{68.44} = 2.0M

<em />

<em>Therefore, the accurate label for the solution is </em><u><em>2.00 mol/L NaCl.</em></u>

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Inferring conclusions if you find an element in nature in its pure elemental state what can you infer about the elements chemica
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Answer;

-Not that reactive

The element found is not very reactive.

Explanation;

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3 years ago
If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?
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Answer:

  • <u>3.0M</u>

Explanation:

The dilution formula is:

       M_1\times V_1=M_2\times V_2

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

  • M₁ = <em>6.0M</em>
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         6.0M\times 251ml=M_2\times 500.ml

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What is the mass of 1.2 mol IrI3?​
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Answer:

690 g IrI₃

Explanation:

To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

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3 years ago
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