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2 years ago

11

Enny and Anne wanted to see who could throw a ball the hardest. They decided to each throw a ball against a wall as hard as they

could and measure how far the ball rolled away from the wall.
Out of the variables that need to be controlled in this experiment, propose how you might control them.

1 answer:

mihalych1998 [28]2 years ago

4 0

Answer:

wha t kind of variables

independent variables

dependent variables

controled variables

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Paano ka nakatutulong upang maiwasan ang suliranin ukol sa climate change

Nostrana [21]

Answer:

hi what is your question?? say in English please

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2 years ago

A 3.0 kg rifle is held firmly by a 50.0 kg woman, initially standing still. A 0.06 kg bullet leaves the rifle muzzle with a velo

ohaa [14]

Answer:

48kg

Explanation:

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7 0

3 years ago

A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2

TEA [102]

The electric field at the surface of the cylinder is 51428V/m

Given data:

• The length of the charge is l= 7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.

The expression to calculate the electric field is given as,

E=2kλ/r

Here, λ is the linear charge density.

Substitute the values in the above equation,

E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m

E = 51428N/C×(V/m)/(N/C)

=51428V/m

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

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brainly.com/question/19886264

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4 0

1 year ago

Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j

AlekseyPX

1) Fundamental units of $\Psi$ are $[\frac{mol}{m\cdot s^2}]$

2) Fundamental units of $\Phi$ are $[\frac{mol}{m^3}]$

Explanation:

The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

where we have:

$\rho$ measured in $[\frac{mol}{ft^3}]$

$\gamma$ measured in $[\frac{J}{kg}]$

$r$ measured in $[in]$

$g$ measured in $[\frac{m}{s^2}]$

We can re-write the equation as

$\rho rg = 2\gamma \Phi + \Psi$

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, $\Psi$ must have the same units of $\rho r g$ . So,

$[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]$

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of $\Psi$ are

$[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]$

2)

The term $2\gamma \Phi$ must have the same units of $\Psi$ in order to be added to it. Therefore,

$[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]$

We also know that the units of $\gamma$ are $[\frac{J}{kg}]$ , therefore

$[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]$

And so, the fundamental units of $\Phi$ are

$[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]$

However, the Joules can be written as

$[J]=[kg][\frac{m^2}{s^2}]$

Therefore

$[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]$

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3 years ago

In the first seconds of flight, the Saturn V rocket achieved an altitude of m, and a velocity of m/s. The rocket weighed approxi

jolli1 [7]

The average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

<h3>Average power produced by the rocket</h3>

The average power produced by the rocket is calculated as follows;

P = FV

where;

P is the average power
F is the force exerted by the rocket
V is the velocity of the rocket

Thus, the average power produced by the rocket is the product of force exerted by the rocket and the velocity of the rocket.

Learn more about average power here: brainly.com/question/19415290

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1 year ago