Answer:
70 g
Explanation:
ice at zero degree will melt and cool down water from 20 degree to 5 degree
heat gained by ice in melting
= mass x heat of fusion
= m x 333.7 x 10³ J
Heat gained by water at zero to water at 5 degree
= mass x specific heat x rise in temperature
= m x 4.18 x 10³ x 5
Total heat gained
= m x 333.7 x 10³ +m x 4.18 x 10³ x 5
= 354.6 x 10³ m J
mass of water = .4 x 1
= .4 kg
heat lost by hot water at 20 degree to 5 degree
= .4 x 4.18 x 10³ x ( 20-5 )
=25.08 X 10³ J
Heat lost = heat gained
354.6 x 10³ m = 25.08 X 10³
m = 25.08 / 354.6
= .070 kg
70 g
b )
Let the water required be m kg
heat gained by water
= m x 4.18 x 10³ x 15
m x 4.18 x 10³ x 15 = 25.08 X 10³
m = 25.08 / (4.18 x 15)
= .4 kg
= 400 gm
=
Answer:
35meV
Explanation:
To find the average translational kinetic energy you use the followinf formula:
K_B: Boltzman' constant = 1.38*10^-23 J/K
T: standard temperature = 273.15K
By replacing these values you obtain:
in eV you have:
5.65*10^-12(6.242*10^18eV)=0.035eV=35meV
Hence, the average translational energy is 35meV
Answer:
Workdone = 0.05Joules
Explanation:
The side of a square =a= 0.510m
q1=q2=3.03×10^-6C
W=UF-Ui
W= kq1q2/a - kq1q2/r
But r= sqrt(a^2+a^2)=sqrt2a
W=kq1q2/a - kq1q1/sqrt2a
W= kq1q2/a (1 -1/sqrt2)
W= (9×10^9)(3.03×10^-6)(3.03×10^-6)(1-1/sqrt2)
W= 0.05Joules
Answer:
Yes
Explanation:
This is because the interaction between piece of paper and earth.is gravitational while that of piece of paper and rod is electrostatic
The increase in temperature of the water is
The total mass of the water is the product between its volume and its density
And so we can find the amount of heat released by the pebble to the water, because this is equal to the amount of heat absorbed by the water, which is