Answer:
The period of the wave does not change looting the value that accompanies the time, the wavelength does not change since it is the constant that accompanies x.
We see that the amplitude is twice the amplitude of the incident waves. Since the wave is stationary the velocity is zero
Explanation:
In this exercise we are given the equation of two traveling waves, it is asked to find the resulting wave
u = f + g
u = 2 sin (x + t) + 2 sin (x-t)
we will develop double angled breasts
u = 2 [(sin x cos t + sin t cos x) + (sin x cos t - sin t cos x)]
u = 2 [2 sin x cos t]
u = 4 sin x cos t
The period of the wave does not change looting the value that accompanies the time, the wavelength does not change since it is the constant that accompanies x.
We see that the amplitude is twice the amplitude of the incident waves. Since the wave is stationary the velocity is zero
The piano strings<span> for </span>low notes<span> are heavier, </span>have<span> more inertia, and </span>vibrate<span> at a lower frequency a lower pitch than lighter </span>strings<span> of the same </span>string<span> tension. Loudness involves how hard the keys are struck, which affects the amplitudes of the </span>vibrating strings<span>. the touch sensitivity of the </span>piano<span> distinguishes it from earlier.
Do you undertand?????
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Answer:
A practical siphon, operating at typical atmospheric pressures and tube heights, works because gravity pulling down on the taller column of liquid leaves reduced pressure at the top of the siphon (formally, hydrostatic pressure when the liquid is not moving).
I hope it's helpful!
Answer:
Leading your people into the right direction, and always knowing what is best for you and your people.
Explanation:
Answer:
<em>The object could fall from six times the original height and still be safe</em>
Explanation:
<u>Free Falling</u>
When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.
If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

Where v is the speed just before hitting the ground
If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

Solving for h

If the drop had occurred in the Moon, then

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g


This means the object could fall from six times the original height and still be safe