1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elena L [17]
2 years ago
15

Stuck at this. Can anyone help me pls? ​

Chemistry
1 answer:
OLEGan [10]2 years ago
3 0
Honestly dude just guess or asks a friend
You might be interested in
Which of the following is true about two neutral atoms of the element zinc?
Ymorist [56]
It isn't specified which neutral atom of zinc it pertains to. There are 5 stable isotopes of Zinc. It could be any of those. However, one thing is true for all possible conditions. These neutral atoms would have the same number of protons because they are of the Zinc element. It would always have 30 protons when neutral. So, the answer is: <span><em>Both have an equal number of protons.</em></span>
8 0
3 years ago
Read 2 more answers
A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568  moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054  moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0
3 years ago
BRAINLIESTTT ASAP!!! PLEASE ANSWER!
sladkih [1.3K]

If the item or substance has changed into a state where you are able to change it back such as:

Water melting

Water freezing

4 0
3 years ago
Read 2 more answers
5. Which of the following can be classified as a mixture ?
podryga [215]

5. B air is a mixture of many elements, but is not a chemically fused.


6. B Beef stew, composition varies throughout.


7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

5 0
3 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

    NO2– + H2O -----> NO3– + 2H+

     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

3 0
3 years ago
Other questions:
  • Butanone draw both enolates formed when the ketone is treated with base. include charges. draw the oxyanion species; do not draw
    5·1 answer
  • Calculate the density of a substance that has a mass of 200 g and volume of 228 ml​
    8·1 answer
  • A solution of calcium chlorate was poured into a sodium fluoride solution. Would you expect a precipitate to form if 255.0 mL of
    15·1 answer
  • The element rhenium (Re) exists as two stable isotopes and 18 unstable isotopes. Rhenium-185 has in its nucleus
    8·1 answer
  • Calculate the shortest wavelength of the electromagnetic radiation emitted by the hydrogen atom in undergoing a transition from
    10·1 answer
  • (URGENT!) Which of these graphs best models the waves in the four locations?<br> (100 points)
    8·1 answer
  • How many moles are in 98.3 grams of NaF?
    10·2 answers
  • What is the scientific notation of (41 e 23) (8.0 e 3)
    11·1 answer
  • Write a well-constructed paragraph on how ionic bonds
    10·1 answer
  • 1. LINE GRAPHS: Line graphs are used when we compare two different number values. 1.1. Draw two graphs on the same set of axes s
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!