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Elena L [17]
2 years ago
15

Stuck at this. Can anyone help me pls? ​

Chemistry
1 answer:
OLEGan [10]2 years ago
3 0
Honestly dude just guess or asks a friend
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Question 4
elixir [45]

Answer:

True

Explanation:

4 0
3 years ago
I have a question for us gals, is it hard for all of you when you try to get your crushes attention and he/she just keeps ignori
Volgvan

Answer:

Yes it is hard. For some of us. I already gave up, but now hes coming back. Id say sometimes its useless to get his attention if he never even pays attention to you anyways. It sucks because its so hard to get then to notice you for once.

Explanation:

4 0
2 years ago
An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
3 years ago
If a snail crawls at 0.013 m/s north, how far will it travel in 60 seconds? Find time.
inessss [21]
It will have traveled 0.78 m. You find this by multiplying .013 by 60
8 0
3 years ago
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Which particles make up the nucleus of an atom?
Anuta_ua [19.1K]
Protons and neutrons
electrons just revolve around it
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3 years ago
Read 2 more answers
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