Answer:
-1.03 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S. I unit of acceleration is m/s².
Mathematically, acceleration is expressed as
a = (v-u)/t ........................ Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time.
Given: u = 13.60 m/s, v = 7.20 m/s t = 6.2 s.
Substituting into equation 2
a = (7.20-13.60)/6.2
a = -6.4/6.2
a = -1.03 m/s²
Note: a is negative because, the hockey puck is decelerating.
Hence the average acceleration = -1.03 m/s²
AB blood would lead to an ABO incompatibility reaction. Hope it helped! (Asked a friend for you to know :D)
Answer:
The magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
Explanation:
The resultant displacement is always the line joining the initial and final position of the vectors.
As in figure,
the vector AB = 35 m
the vector BC = 15 m
the angle between AB and AC = 25' (minutes)
the resultant vector AC = ?
The resultant vector is given by the formula
AC² = AB² + BC² + 2 AB BC Cos θ
Substituting the values in the equations,
AC² = 35² + 15² + 2 x 35 x 15 x Cos 25'
= 56.54
Therefore, the magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
Answer:
V= 14.2m/s
Explanation:
We know that acceleration= dv/dt
So 16m/s²=dv/ dt = v dv/ds
So this wil be
Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]
So 16[s (3/2)/3/2] at ( s,3) = v²/2
At s= 6m
So v² = 64/3( 6^1.5-3^1.5)
= 14.2m/s
Explanation:
It is given that,
Radius of bowl, r = 3 m
A small block is released from rest from the edge of a large hemispherical friction less bowl. Let v is the speed of the mass when it passes through the bottom of the bowl and u is the initial speed of the mass, u = 0. Using conservation of energy as :

h = r = 3 m


v = 7.66 m/s
or
v = 7.7 m/s
So, the speed of the mass at the bottom of the bowl is 7.7 m/s. Hence, this is the required solution.