Answer:
B) The same as the momentum change of the heavier fragment.
Explanation:
Since the initial momentum of the system is zero, we have
0 = p + p' where p = momentum of lighter fragment = mv where m = mass of lighter fragment, v = velocity of lighter fragment, and p' = momentum of heavier fragment = m'v' where m = mass of heavier fragment = 25m and v = velocity of heavier fragment.
0 = p + p'
p = -p'
Since the initial momentum of each fragment is zero, the momentum change of lighter fragment Δp = final momentum - initial momentum = p - 0 = p
The momentum change of heavier fragment Δp' = final momentum - initial momentum = p' - 0 = p' - 0 = p'
Since p = -p' and Δp = p and Δp' = -p = p ⇒ Δp = Δp'
<u>So, the magnitude of the momentum change of the lighter fragment is the same as that of the heavier fragment. </u>
So, option B is the answer
Answer:
0.26seconds
Explanation:
Impulse is the product of force and time
Impulse =Force * Time
Given
Impulse = 67Ns
Force = 257N
Required
Time
From the formula;
Time = Impulse/Force
Time = 67/257
Time = 0.26s
Hence the amount of time is 0.26seconds
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