Answer:
|Δf| = 37.3 kHz
Explanation:
given,
peak velocity = 4 m/s
speed of the sound = 1500 m/s
frequency = 7 MHz




= 37.3 kHz
|Δf| = 37.3 kHz
hence, frequency shift between the opening and closing valve is 37.3 kHz
Earth is 150 million kilometers away for the sun
Answer:
Key components of games are goals, rules, challenge, and interaction.
Explanation:
Hope I helped.
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
- Density of the ice, ρ = 917 kg/m³
- Initial pressure, P₁ = 1.0 bar
- Final pressure, P₂ = 2.0 bar
- Temperature, T = - 10 C
- Mass of water = 18 g
The change in the Gibb's free energy per mole (G) is calculated as follows;

where;
V is the volume of the ice

Change in pressure;

The change in the Gibb's free energy per mole (G);

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
Learn more about Gibb's free energy here: brainly.com/question/10012881
Given: v0= 18.0 m/s, y0=0m, yf=11m, g=-9.81 m/s^2
v0= initial velocity, vf= final velocity, y0= initial height, yf= final height, g= gravity, sqrt()= square root, ^2=squared
vf^2=v0^2 + (2)(g)(yf-y0)
vf^2=(18.0 m/s)^2+(2)(-9.81 m/s^2)(11 m-0m)
vf^2=18.0 m/s)^2 + (-19.62 m/s^2)(11 m)
vf^2=(324 m^2/s^2) - (215.82 m^2/s^2)
vf^2=108.18 m^2/s^2
vf=sqrt(108.18 m^2/s^2)
vf=10.4 m/s