Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
If you are moving the center of circle 2 to the the center of circle 1, then the translation rule is (x,y) ---> (x+4, y+10).
Note how x = 1 turns into x = 5. So we add 4
Also, y = -2 turns into y = 8. We add 10
The scale factor to turn the radius r = 4 into r = 8 is 2. Basically we double the radius. We can divide the two radii to see 8/4 = 2
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Summary:
To go from circle 2 to circle 1, we apply these two transformations
translation: (x,y) ---> (x+4, y+10)
dilation: scale factor 2
note:
if you want to go backwards, go from circle 1 to circle 2, then undo the transformations above
If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
It is given that line segment BC is congruent to line segment EC and that line segment AC is congruent to DC. Because of the vertical angles theorem, angle BCA is equal to angle DCE. Therefore, triangles CBA AND DEC are congruent by SAS. Using CPCTC, BA is equal to ED.
