2N2O5(g)----> 4NO2(g) + O2(g)
<span>[N2O5]i (M) Initial Rate(M^-1 s^-1) </span>
<span>0.093 4.84x10^-4 ---- (1) </span>
<span>0.186 9.67x10^-4 ----- (2) </span>
<span>0.279 1.45x10^-3 ----- (3) </span>
<span>From equation (1) & (2) it is evident that when [N2O5}i is doubled the initial rate is doubled, which implies the rate is directly proportional to [N2O5]. Similarly comparing equation (1) & (3) we observe that when [N2O5] is tripled the rate is also tripled. Hence the rate equation is </span>
<span>Rate = k [N2O5] </span>
<span>Using the data of any equation, say (1), we get </span>
<span>4.84x10^-4 = k x 0.093 </span>
<span>OR k = 4.84x10^-4/0.093 = 5.2 x 10^-3 s-1 </span>
<span>Hence the rate law is </span>
<span>Rate = 5.2 x 10^-3 s-1[N2O5]</span>
Answer:
C
Explanation:
Temperature is the measure of "hotness" of a system. When temperature increases, the kinetic energy of the particles increase. So they will collide with greater energy per collision.