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Over [174]
3 years ago
14

The primary goal of water-softening ion exchange systems is _____(1 point)

Chemistry
1 answer:
Anettt [7]3 years ago
5 0

Answer:

The primary goal of water-softening ion exchange systems is _____(1 point)

removing magnesium and calcium from water. ***

removing sodium from water.

introducing magnesium and calcium into water.

introducing sodium into water.

How does a reverse osmosis water purification system operate? (1 point)

Untreated water is subjected to high pressure, causing it to move through a highly permeable membrane, which captures contaminants.

Untreated water is subjected to high pressure, causing it to move through a semi-permeable membrane, which captures contaminants. ***

Untreated water is subjected to low pressure, causing it to move through a highly permeable membrane, which captures contaminants.

Untreated water is subjected to low pressure, causing it to move through a semi-permeable membrane, which captures contaminants.

A city council is debating between two potential water purification systems: reverse osmosis and ion exchange. Cost is the primary criteria for the choice. Which decision is the most likely result of this debate?(1 point)

More research is needed because reverse osmosis systems require specialized maintenance, while ion exchange requires regular replacement of components. ***

A reverse osmosis system would likely be chosen because it does not require specialized maintenance or regular replacement of components.

More research is needed because ion exchange systems require specialized maintenance, while reverse osmosis requires regular replacement of components.hdhdhd

An ion exchange system would likely be chosen because it does not require specialized maintenance or regular replacement of components.

A city council is debating different alternatives for purifying water from a local reservoir. The council is considering ion exchange and reverse osmosis. Bacterial contamination of the water supply is the primary concern, and the council has decided that dealing with this is the main criteria for their choice. Which decision is the most likely outcome of this debate?(1 point)

They are likely to choose reverse osmosis because it is specifically designed to kill bacteria.

They are likely to choose ion exchange because it is specifically designed to kill bacteria.

They are likely to choose reverse osmosis because it addresses a wider range of problems, including bacteria. ***

They are likely to choose ion exchange because it addresses a wider range of problems, including bacteria.

Which of the following is a constraint of a chlorine bleach shock to remove contaminants from drinking water?(1 point)

This treatment only removes large solids.

This treatment only removes microscopic contaminants.

This treatment does not remove bacteria.

This treatment removes bacteria, but not other pollutants. ***

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Write the balanced equation for the ionization of the weak base pyridine, c5h5n , in water, h2o. Phases are optional.
Lelu [443]

The balanced equation for the ionization of the weak base pyridine,C5H5N in water, H2O

C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)

<h3>What is the balanced equation for the ionization?</h3>

Generally, Pyridine is characterized by a ring structure, in this characteristic ring structure N is sp2 hybridized, hence creating a lone pair present on N so s - character is more, as well as lone pair, is present.

Therefore, Considering The following functions of the equation:weak base pyridine,C5H5N in water, H2O

We write the balanced equation for the ionization as

C_5H_5N ( aq.) + H2O ( l) ---------> C5H5NH+ (aq.) + OH- (aq.)

Read more about  Chemical Reaction

brainly.com/question/11231920

6 0
2 years ago
The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

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3 years ago
Facing the wind. A) windward B) subaric C) monsoon D) biotic
SpyIntel [72]
I think B
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Help I will give brainlest
RoseWind [281]

Answer:

grasslands ia the answer!

3 0
3 years ago
Convert 0.950 atm of pressure to its equivelant in millimeters of mercury
Jet001 [13]
1 atm = 760mmHg

0.950 atm = (0.950 atm) * (1 atm) = 0.95

Answer: 0.96 mmHg
6 0
3 years ago
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