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Alexxandr [17]
2 years ago
13

Find the geometric mean of 8 and 253.

Mathematics
1 answer:
qaws [65]2 years ago
7 0

Answer:

2√506

Step-by-step explanation:

√8x253  =  √2024 =  √4x506 = 2√506

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¿Cuál es el área de un rectángulo, sabiendo que su perímetro mide 24 cm y que su base es el triple de su altura?
Brrunno [24]

Answer:

El área del rectángulo es:

27 cm²

Step-by-step explanation:

Consideración:

La formula del perímetro de un rectángulo es:

p = 2(altura + base)

Planteamiento:

24 = 2(a+b)

b = 3a

a = longitud de la altura del rectángulo

b = longitud de la base del rectángulo

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

24 = 2(a + 3a)

24/2 = 4a

12 = 4a

a = 12/4

a = 3 cm

de la segunda ecuación del planteamiento:

b = 3a

b = 3*3

b = 9 cm

Comprobación:

de la primer ecuación del planteamiento:

24 = 2(3+9)

24 = 2*12

Respuesta:

la formula del área de un rectángulo es:

A = base * altura

A = 9cn * 3cm

A = 27cm²

5 0
3 years ago
A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
3 years ago
What is the answer please really stuck ​
Pavlova-9 [17]

Answer:

X is 30

Step-by-step explanation:

X is 30

23 plus 8 times 2

4 0
3 years ago
Read 2 more answers
How do you round 243.876 to the nearest tenth, hundredth, ten and thousands
kompoz [17]
Nearest tenth 243.9
nearest hundredth 243.88
nearest thousand 243.876
nearest ten 244
6 0
3 years ago
How many three letter permutations can be formed from the first five letters of the alphabet?
Vsevolod [243]

Answer:

There are 60 permutations that can be formed from the first five letters of the alphabet.

Step-by-step explanation:

The number of three letter permutations that can be formed from the first five letters of the alphabet is 5P_{3}.

5P_{3} =\frac{5!}{(5-3)!}

=\frac{5!}{2!}

= 60

Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.

6 0
3 years ago
Read 2 more answers
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