The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mole of CCl₄</h3>
- Mass of CCl₄ = 30 g
- Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
- Mole of CCl₄ =?
Mole = mass / molar mass
Mole of CCl₄ = 150 / 154
Mole of CCl₄ = 0.974 mole
Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.
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Answer:
19.39 mL.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have different values of V and T:
<em>(V₁T₂) = (V₂T₁)</em>
<em></em>
V₁ = 22.8 mL, T₁ = 48°C + 273 = 321 K,
V₂ = ??? mL, T₂ = 273 (standard temperature = 273 K),
- Applying in the above equation
<em>(V₁T₂) = (V₂T₁)</em>
<em />
∴ V₂ = (V₁T₂)/(T₁) = (22.8 mL)(273 K)/(321 K) = 19.39 mL.
<em>Answer:</em>
<em>Mr.clark is prescribed 500 mg of acetaminophen TID and 30 ml of prednisone BID. Mr.clark takes his first dose of both medications at 0800 hours when would you administer the second dose of acetaminophen?
</em>
<em>Mr. Clark is prescribed 500 mg of acetaminophen TID and 30 ml of prednisone BID. Mr. Clark takes his first dose of both medications at 0800 hours. [ You would administer the second dose of acetaminophen at 1400 hours. ]</em>
KOH is the limiting reagent
The molar ratio is 1:2
So if you have 6 moles of MgCl2 you need 12 moles of KOH
N2o5 would diffuse more slowly
