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Murrr4er [49]
4 years ago
7

9) A 22.8 mL volume of argon gas is collected at 48.0o​ ​C. At constant pressure, what volume would this same sample of gas occu

py at standard temperature?
Chemistry
1 answer:
irakobra [83]4 years ago
3 0

Answer:

19.39 mL.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have different values of V and T:

<em>(V₁T₂) = (V₂T₁)</em>

<em></em>

  • Knowing that:

V₁ = 22.8 mL, T₁ = 48°C + 273 = 321 K,

V₂ = ??? mL, T₂ = 273 (standard temperature = 273 K),

  • Applying in the above equation

<em>(V₁T₂) = (V₂T₁)</em>

<em />

∴ V₂ = (V₁T₂)/(T₁) = (22.8 mL)(273 K)/(321 K) = 19.39 mL.

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