According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
Answer:
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
Explanation:
<u>Step 1:</u> Data given
Wine 1 has a pH of 3.5
Wine 2 has a pH of 2.9
Wine 2 is more acid so should have more hydrogen ions
<u>Step 2:</u> Calculate hydrogen concentration
pH = -log [H+]
Wine 1: pH = 3.5 = -log[H+]
[H] = 10 ^-3.5 M = 0.00032 M
Wine 2: pH =2.9 = -log[H+]
[H+] = 10^-2.9 = 0.00126 M
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
The italian white wine has a higher concentration of hydrogen ions, what means it's more acid than the californian red wine.
Answer:
<u>The deviations are :</u>
- <u>The activation energy which changes with temperature</u>
- <u>The arrhenius constant which depends on the temperature</u>
Explanation:
- There are deviations from the Arrhenius law during the glass transition in all classes of glass-forming matter.
- The Arrhenius law predicts that the motion of the structural units (atoms, molecules, ions, etc.) should slow down at a slower rate through the glass transition than is experimentally observed.
- In other words, the structural units slow down at a faster rate than is predicted by the Arrhenius law.
- <em>This observation is made reasonable assuming that the units must overcome an energy barrier by means of a thermal activation energy. </em>
- The thermal energy must be high enough to allow for translational motion of the units <em>which leads to viscous flow of the material.</em>
- Both the Arrhenius activation energy and the rate constant k are experimentally determined, and represent macroscopic reaction-specific parameters <em>that are not simply related to threshold energies and the success of individual collisions at the molecular level. </em>
- Consider a particular collision (an elementary reaction) between molecules A and B. The collision angle, the relative translational energy, the internal (particularly vibrational) energy will all determine the chance that the collision will produce a product molecule AB.
- Macroscopic measurements of E(activation energy) and k(rate constant ) <em>are the result of many individual collisions with differing collision parameters. </em><em>They are averaged out to a macroscopic quantity.</em>
