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LUCKY_DIMON [66]
3 years ago
5

What are the elements in an ionic bond?

Chemistry
2 answers:
miss Akunina [59]3 years ago
5 0

Answer:

Ionic bonds require an electron donor, often a metal, and an electron acceptor, a nonmetal. Ionic bonding is observed because metals have few electrons in their outer-most orbitals. By losing those electrons, these metals can achieve noble gas configuration and satisfy the octet rule.

Explanation:

KIM [24]3 years ago
4 0

Answer:

Metal and non-metal

Explanation:

For exp, sodium (metal) and chloride (non-metal) form an ionic bond to make NaCl.

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A homuncule broke my spondyle and stole my effusiometer without even paying a weighage! I just got out of the hospital, one heck
Scilla [17]

Answer:

You should definitely consult your doctor for the serious brain damage caused.

7 0
2 years ago
An aluminum can has a height of 4.83 inches, a diameter of 2.60 inches, and a uniform wall/end thickness of 0.0112 inches. If th
Triss [41]
Strategy: with the measures you can determine the volume of the plate of aluminum. Then you can use the density of aluminum to calculate the mass.

With the mass of aluminum and its atomic mass you can find the number of moles and thereafter the number of atoms.

Finally divide the cost by the number of atoms to find the cost of one single atom.

Let's do it.

Volume of aluminum plate, V: 0.0112 in* 4.83 in* 2.60 in * [2.54 cm/in]^3 = 2.305 cm^3

Density of aluminum (from Wikipedia), d = 2.70 g/cm^3

mass, m = d*V = 2.305 cm^3 * 2.70 g/ cm^3 = 6.22 g

Atomic mass of aluminum (from Wikipedia), am = 27 g / mol

Number of moles, n = m/am = 6.22 g / 27 g / mol =   0.23 mol

Number of atoms = n*Avogadro constant = 0.23 mol * 6.022 * 10^23 atoms/mol = 1.39*10^23

Cost per atom = cost of the can / number of atoms =$ 0.05 /1.39*10^23 atoms  =  3.60 * 10^ - 25 $/atom
4 0
3 years ago
Open-ended question: Differentiate between a solution and a two phase mixture. Brass is would be classified as which one of them
Mariana [72]
I would classify the salad as a mixture because you can separate the components<span />
4 0
3 years ago
If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess react
lys-0071 [83]

Answer:

m_{FeCl_2}=0.652gFeCl_2

Explanation:

Hello there!

In this case, according to the given information and the chemical reaction, whereby iron and hydrochloric acid react in a 1:2 mole ratio, it is firstly necessary to calculate the moles of iron (II) chloride from each reactant in order to figure out the limiting reactant:

n_{FeCl_2}=2.45gFe*\frac{1molFe}{55.845gFe}*\frac{1molFeCl_2}{1molFe}=0.0439molFeCl_2\\\\  n_{FeCl_2}=1.5L*0.25\frac{molHCl}{L} *\frac{1molHCl}{36.46gHCl}*\frac{1molFeCl_2}{2molHCl}=0.00514molFeCl_2

In such a way, we infer the maximum moles of FeCl2 product are yielded by HCl, for which it is the limiting reactant. Finally, we calculate the grams of product by using its molar mass as shown below:

m_{FeCl_2}=0.00514molFeCl_2*\frac{126.75gFeCl_2}{1molFeCl_2} \\\\m_{FeCl_2}=0.652gFeCl_2

Regards!

7 0
3 years ago
HELP ASAP PLS <br> Reactions, products and leftovers
Alenkasestr [34]

Answer:

See the answer below

Explanation:

From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.

Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.

Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.

<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>

3 0
3 years ago
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