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MatroZZZ [7]
2 years ago
5

What is the distance between A(-3, 7) and B(3, 7)?

Mathematics
1 answer:
olga55 [171]2 years ago
8 0

Answer:

6 units between A and B

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HELP ME PLZ I NEED 100 ON ThIS SO GET ME RIGHT I WELL GIVE BAIRELEST
Alex_Xolod [135]

Answer:

pretty sure its c

Step-by-step explanation:

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The 25 coins in Danielle's piggy bank have a value of at least $1.44. The bank contains only nickels and dimes. What is the fewe
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Should be 3 dimes at least.
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What is the interquartile range (IQR) of the data set represented by this box
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3 years ago
Question<br> Write the word sentence as an inequality.<br><br> A number y is no more than −8.
vekshin1

Hey there mate ;)

As per question :-

<em>Write the word sentence as an inequality</em><em>.</em><em> </em><em>A number y is no more than −8.</em>

To make the sentence as an inequality, the answer will be:-

<h2> <u>y < -8</u></h2>

Reason:-

By considering 'y' as a number, it is told that the number is not bigger than the value -8. So, by simple arithmetic, the answer will be <em>y</em><em> </em><em><</em><em> </em><em>-8</em>

5 0
3 years ago
Height of Dutch Men. Males in the Netherlands are the tallest, on average, in the world with an average height of 183 centimeter
trapecia [35]

Answer:

a) P(X

P(z

b) P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

P(z>1.143)=1-P(Z

c) P(173

P(-0.953

P(-0.953

d) P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(183,10.5)  

Where \mu=183 and \sigma=10.5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard table or with excel:

P(z

Part b

P(X>195)

P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

And we can find this probability with the normal standard table or with excel: using the complement rule

P(z>1.143)=1-P(Z

Part c

P(173

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(173And we can find this probability on this way:

P(-0.953

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.953Part d

Since the distributiion for X is normal then the distribution for the sample mean is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we eant this probability:

P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

3 0
3 years ago
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