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maks197457 [2]
2 years ago
7

Identify each definition that applies to the compound in red. Check all that apply. HCI NaOH → H2O NaCl Arrhenius acid Bronsted-

Lowry acid Arrhenius base Bronsted-Lowry base.
Chemistry
1 answer:
Nata [24]2 years ago
8 0
An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition).
A base is a substance that can accept protons or donate a pair of valence electrons to form a bond.
Bases can be thought of as the chemical opposite of acids. A reaction between an acid and base is called a neutralization reaction.
The strength of an acid refers to its ability or tendency to lose a proton; a strong acid is one that completely dissociates in water.
You might be interested in
The radioactive atom 61/27 co emits a beta particle. write an equation showing the decay
pickupchik [31]

Answer:

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}

Explanation:

The unbalanced nuclear equation is

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

60 = 0 + A, so A = 60 - 0 = 60, and

27 = -1 + Z, so Z  = 27 + 1 = 28

Your nuclear equation becomes

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{X}

Element 28 is nickel, so the balanced nuclear equation is

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}

7 0
3 years ago
can someone explain in detail how molar mass, Avogadro's number, and volume are all connected through moles? Im so confused :(
sashaice [31]

Answer:

See Explanation

Explanation:

By definition, 1 mole is the mass of substance (or, formula mass in grams) containing 1 Avogadro's Number (N₀ = 6.02 x 10²³) of particles. That is ...

1 mole of hydrogen atoms (H) = 1.00794 grams

1 mole of molecular hydrogen (H₂) =  2.01588 grams

1 mole of any substance = 1 formula weight in grams

1 mole = 1 Avogadro's Number (N₀) = 1 formula weight in grams

In the concept of 'gas laws' 1 mole of any (all) gas at STP conditions ( => 0°C & 1 atmosphere pressure) occupies 22.4 Liters & is known as the 'molar volume' of a gas at STP. If the temperature &/or pressure change the volume will not be 22.4 Liters.

For reactions whose coefficients are balanced to the lowest whole number values (i.e., no fractional coefficients) the equation is known as the 'standard reaction' and conditions  are assumed to be STP and the coefficients of gas phase components indicate molar volumes. Example ...

Given   N₂(g) + 3H₂(g) => 2NH₃(g)  is assumed to be at 0°C; 1 Atm pressure.

Molecular Nitrogen = 1 molar volume = 22.4 Liters of N₂(g)

Molecular Hydrogen = 3 molar volumes = 3 x  22.4 Liters of H₂(g) = 67.2 Liters of H₂(g)

Molecular Ammonia = 2 molar volumes = 2 x 22.4 Liters of NH₃(g) = 44.8 Liters of NH₃

8 0
3 years ago
Empirical formula of a compound if a 50.0 g sample of it contains 9.1g Na ,20.6 g Cr ,and 22.2 g O
denpristay [2]

Answer:

The empirical formula of a compound is Na2Cr2O7

Explanation:

Empirical formula is defined as the lowest ratio of elements present in any substance. In order to determine the empirical formula for a substance containing these elements we have to follow some steps.

1.In the first step, we have to divide the given mass of an element with its molecular mass to convert the mass to moles.

No. of moles of Na=Given Mass of Na/Molecular Mass of Na=9.1/23=0.396

Similarly, the moles of Cr and O in that compound were calculated and found as 0.396 and 1.3875, respectively.

2. Then the next step is to determine the lowest moles and divide all the moles with that lowest mole. As here the lowest mole is 0.396. So on dividing the moles of Na, Cr and O with 0.396, we will obtain the ratio as 1:1:3.5.

3. As the ratio consists of a fractional number, we have to multiply it with the smallest possible integer to convert it to whole number. In this case, if we multiply it with 2 , we will get the ratio as 2:2:7.

Thus, the empirical formula for the compound can be written as Na2Cr2O7.

5 0
4 years ago
Sodium and magnesium ions have 10 electrons surrounding their nuclei which ion would you expect to have the larger radius why
Maksim231197 [3]
Sodium because according to the atomic size trend of the periodic table. Elements further to the left are bigger while elements tot he right are smaller. This is also do to their charges, Na has a +1 charge meaning it doesn’t pull the electrons as close as the Mg does with its +2 charge.

8 0
4 years ago
Arsine, AsH3, is a highly toxic compound used in the electronics industry for the production of semiconductors. Its vapor pressu
lara31 [8.8K]

Answer:

-79.8 × 10⁴ J/mol

Explanation:

<em>Arsine, AsH₃, is a highly toxic compound used in the electronics industry for the production of semiconductors. Its vapor pressure is 35 Torr at 111.95 °C and 253 Torr at 83.6 °C.</em>

<em />

Then,

P₁ = 35 torr

T₁ = 111.95 + 273.15 = 385.10 K

P₂ = 253 torr

T₂ = 83.6 + 273.15 = 356.8 K

We can calculate the standard enthalpy of vaporization (ΔH°vap) using the two-point Clausius-Clapeyron equation.

ln(\frac{P_{2}}{P_{1}} )=\frac{-\Delta H\°_{vap}}{R} .(\frac{1}{T_{2}} -\frac{1}{T_{1}} )

where,

R is the ideal gas constant

ln(\frac{253torr}{35torr})=\frac{-\Delta H\°_{vap}}{8.314J/K.mol} .(\frac{1}{356.8K}-\frac{1}{385.10K})\\ \Delta H\°_{vap}=-79.8 \times 10^{4} J/mol

6 0
3 years ago
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