All categories

3 years ago

Which describes electricity?

Physics

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Answer:

all of the above

Explanation:

- a build up of electric charge

- the force and motion of electrically charged particles

- an electric current

are three different ways to describe electricity.

So the answer is all of the above.

You might be interested in

When the displacement in SHM is one-half the amplitude xm, what fraction of total energy is (a) kinetic energy and (b) potential

Svet_ta [14]

Answer:

Explanation:

7 0

2 years ago

URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you ha

Liono4ka [1.6K]

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

4 0

3 years ago

⚠️ PLEASE HELP ⚠️

Svetllana [295]

Answer:

-79.6

-80

-81.2

Explanation:

5 0

4 years ago

Read 2 more answers

A level curve on a country road has a radius of 150 m. What is the maximum speed at which this curve can be safely negotiated on

SSSSS [86.1K]

The maximum speed of the car is 24.3 m/s

Explanation:

For a car moving along an unbanked turn, the frictional force provides the centripetal force required to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force while the term on the right is the centripetal force, and where

$\mu=0.40$ is the coefficient of friction between the tires and the road

m is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

v is the speed of the car

r = 150 m is the radius of the curve

Solving for v, we find the (maximum) speed at which the car can move along the turn:

$v=\sqrt{\mu gr}=\sqrt{(0.40)(9.8)(150)}=24.3 m/s$

For speed larger than this value, the frictional force is no longer enough to keep the car along the turn.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0

3 years ago

Uploaded imageTwo long, parallel wires each carry the same current I in the same direction (see figure below). The total magneti

LekaFEV [45]

Answer:

Zero

Explanation:

Two long parallel wires each carry the same current I in the same direction. The magnetic field in wire 1 is given by :

$B_1=\dfrac{\mu_oI_1}{2\pi r}$

Magnetic force acting in wire 2 due to 1 is given by :

$F_{2}=I_2lB_1$

$F_2=\dfrac{\mu_oI_1I_2 l}{2\pi r}$

Similarly, force acting in wire 1 is given by :

$F_1=\dfrac{\mu_oI_1I_2 l}{2\pi r}$ According to third law of motion, the force acting in wire 1 will be in opposite direction to wire 2 as :

$F_2=-F_1$

So, the total magnetic field at the point P midway between the wires is in what direction will be zero as the the direction of forces are in opposite direction.

7 0

3 years ago