Consider the hydrate below. FeCl3•6H2O
1 answer:
So this is nomenclature.
The name would be Iron (III) Chloride Hexahydrate
Reason why it's Iron (III) is because of the 3 after Cl, if you take FeCl3 apart it's
and Cl^-.
Hexahydrate because hexa = 6 and hydrate=water
The term hydrate would be wrong because that clearly doesn't come first
It would be the anhydrous compound that comes first. The "an" in "anhydrous" means "without". Hydrous=water, so anyhdrous= without water
The part without water is FeCl3. The water is 6H2O
The prefix for the coefficient of water is 6, or hexa, but that's not first in the name
The name would be Iron (III) Chloride Hexahydrate
Reason why it's Iron (III) is because of the 3 after Cl, if you take FeCl3 apart it's
Hexahydrate because hexa = 6 and hydrate=water
The term hydrate would be wrong because that clearly doesn't come first
It would be the anhydrous compound that comes first. The "an" in "anhydrous" means "without". Hydrous=water, so anyhdrous= without water
The part without water is FeCl3. The water is 6H2O
The prefix for the coefficient of water is 6, or hexa, but that's not first in the name
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Answer:
0.088 M.
Explanation:
Assuming that the temperature is 429 K, we can calculate the concentration of NO₂. Kc(429K) = 0.490.
The reaction is:
N₂O₄(g) ⇄ 2NO₂(g)
0.04 0.04
0.04 - x 0.04 + 2x
The constant of the reaction is:
By solving the above equation for x we have:
x = 0.024 = [NO₂]
Hence the concentration of NO₂ is:
I hope it helps you!