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m_a_m_a [10]
3 years ago
9

Help me please this delta math has to be done today

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

B.

21---------------->7

24--------------->8

27--------------->9

Step-by-step explanation:

Since there are 21 cheesecakes for every 7 blocks of cream cheese, we can set up the an equation

So that means there are 3 cheesecakes for every block of cream cheese

So we can create a table

3----------------->1

6------------------>2

9----------------->3

12---------------->4

15---------------->5

18---------------->6

21---------------->7

24--------------->8

27--------------->9

The equation would be:

y = 3x

21 = 3(7)

xz_007 [3.2K]3 years ago
3 0

hola ny yo no puedo y quiero la respuesta

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3xy^3+5-x-2xy^3=xy^3+11
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Answer:  x=-6

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Step-by-step explanation:

 Step 1: Add -xy^3 to both sides.

xy^3-x+5+-xy^3=xy^3=xy^3+11+-xy^3

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Step 2: Add -5 to both sides.

-x+5+-5=11+-5\\-x=6

Step 3: Divide both sides by -1.

\frac{-x}{-1} =\frac{6}{-1}

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Please help me with number five WHOEVER EXPLAINS AND GIVES ME THE ANSWER GETS BRAINLEST
MrMuchimi
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If an arrow is shot upward on Mars with a speed of 62 m/s, its height in meters t seconds later is given by y = 62t − 1.86t². (R
Soloha48 [4]

Answer:

Approximately 58.28\; \rm m \cdot s^{-1}.

Step-by-step explanation:

The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.

Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height: y = 62\, t - 1.86\, t^2.

Apply the power rule to find the first derivative of this y with respect to time t.

By the power rule:

  • the first derivative of t (same as
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Therefore:

\begin{aligned}\frac{dy}{d t} &= \frac{d}{d t}\left[62 \, t - 1.86\, t^2\right] \\ &= 62\,\left(\frac{d}{d t}\left[t\right]\right) - 1.86\, \left(\frac{d}{d t}\left[t^2\right]\right) \\ &= 62 \times 1 - 1.86\times\left(2\, t) = 62 - 3.72\, t\end{aligned}.

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