How are nutrients, vitamins and minerals transported from the digestive tract to the cells though out the body?

Si se aparean especies diferentes como por ejemplo el cruce entre caballos y burros; podemos afirmar que si llegan a tener desce

White raven [17]

Answer:

El híbrido va a ser esteril.

Explanation:

En la cruza entre dos especies distintas, cuando ocurre, existen distintos mecanismos de aislamiento reproductivo, que son barreras que inhiben o interrumpen el flujo génico entre especies distintas. Es decir que no habrá exito reproductivo de estas cruzas. Se trata de caracteres biológicos propios de cada especie que previenen la reproducción con otras especies.

Estos mecanismos de aislamiento reproductivo pueden ser precigóticos o postcigóticos.

1.Pre-copulatorios o pre-cigóticos:

Ecológico o por aislamiento de hábitat;

Estacional o temporal;

Sexual o etológico;

Mecánico;

Por incompatibilidad de gametas.

2. Post-copulatorios o cigóticos:

Inviabilidad del híbrido;

Esterilidad del híbrido;

Híbrido con viabilidad o fertilidad disminuido;

Interacciones citoplasmáticas.

La mula es producto de la cruza entre dos especies distintas: una yegua (Equus ferus caballus) y un burro (Equus africanus asinus). Es un ejemplo de la accion de mecanismo poscigótico, en el cual se forma un híbrido viable esteril. Este ejemplar puede nacer, crecer y sobrevivir, pero que no puede producir gametas funcionales, por lo cual no puede reproducirse.

7 0

2 years ago

UITIVEise dlu

Roman55 [17]

Answer:

14 bilion years old

Explanation:

6 0

3 years ago

A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

--------------------------

Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

brainly.com/question/9870841?referrer=searchResults

brainly.com/question/419732?referrer=searchResults

brainly.com/question/13603001?referrer=searchResults

brainly.com/question/5028378?referrer=searchResults

6 0

2 years ago

How the data from the temperature experiment supports your hypothesis.

Kipish [7]

Wheres the picture for this