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2 years ago

If ke is proportional to time, what is acceleration proportionate to:.

Physics

1 answer:

ElenaW [278]2 years ago

6 0

It’s proportional to net force

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How many different atoms are there in a compound?

yKpoI14uk [10]

Answer:

2 or more atoms

Explanation:

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7 0

2 years ago

Read 2 more answers

An airplane flies at airspeed (relative to the air) of 280 km/h . The pilot wishes to fly due North (relative to the ground) but

MrRa [10]

Answer:

the pilot should head the plane $7.547^{\circ}$ towarrds south- west

Solution:

The airspeed of the airplane, v = 280 km/h

The velocity of the wind, v' = 52 km/h South-west

Angle, $\theta = 225^{\circ}$

Now, measured angle in the clockwise direction from North:

$sin225 = sin(\pi + 45) = - sin 45^{\circ}$

Now,

$vsinx - v'sin45 = 0$

$280sinx = 52sin45$

$x = sin^{- 1}(\frac{52}{280}\times \frac{1}{\sqrt{2}})$

$x = 7.547^{\circ}$ south- west

4 0

3 years ago

A 64 kg swimmer jumps, with a velocity of 4.2 m/s, off the front of a 25 kg kayak when the kayak is moving forward at a velocity

Crank

Answer:

3.88m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and 2 are the initial velocities

v is the final velocity

Given

m1 = 64kg

u1 = 4.2m/s

m2 = 25kg

u2 = 3.2m/s

Required

Final velocity v

Substitute the given values into the formula

64(4.2)+25(3.2) = (65+25)v

268.8+80 = 90v

348.8 = 90v

v = 348.8/90

v = 3.88m/s

Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s

8 0

2 years ago

A. 24.89<br> B. 25.89<br> C. 17.74<br> D. 19.73

Veronika [31]

Answer: D

Explanation:

Just did it got an 100

5 0

2 years ago

A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th

vladimir1956 [14]

Answer:

Force, $F=2.27\times 10^4\ N$

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

$F=\dfrac{-mu^2}{2d}$

$F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}$

F = -22713.92 N

$F=2.27\times 10^4\ N$

So, the magnitude of the force that stops the bullet is $2.27\times 10^4\ N$

7 0

2 years ago