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scoray [572]
3 years ago
6

What are the zeros of the polynomial function f(x) = x3 + 2x2 − 24x?

Mathematics
1 answer:
Alik [6]3 years ago
4 0

You may notice that all of the terms have a common factor: x. So, let's take the x out of all the terms. This gives us:

x(x^2 + 2x - 24) = 0


Using the Zero Product Property, we can say that both x = 0 and x^2 + 2x - 24 = 0.

Let's solve both. x = 0 is obvious, but we still need to solve our other term:

x^2 + 2x - 24 = 0

  • Set up

(x + 6)(x - 4) = 0

  • Factor

x = -6, 4

  • Apply the Zero Product Property

Our answer is x = -6, 0, 4.


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Scores from an exam are normally distributed with a mean of 85 and a standard deviation of 5. Suppose 188 students take the exam
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The mean is \mu=85 and standard deviation is \sigma=5. Then the variable X\sim N(85,5).

Use substitution Z=\dfrac{X-\mu}{\sigma}=\dfrac{X-85}{5}, then the variable Z\sim N(0,1).

The probability Pr(X>80) can be calculated in the following way:

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