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grandymaker [24]
3 years ago
8

2. State the right of a citizen.

Physics
1 answer:
suter [353]3 years ago
8 0

Explanation:

1. - right to vote

- the right to elect to be elected and so on.

2.

- respect the rule of counrty

- pay taxs

- keeping the sovernitry of country

- make the counrty stable

- respect the diversity

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A 5.0-Ω resistor and a 9.0-Ω resistor are connected in parallel. A 4.0-Ω resistor is then connected in series with this parallel
lbvjy [14]
The 4ohm resistor is not parallel to any devices, so the current through it is the same as the total current through the circuit.

Apply I = V/R
I = total current, V = battery voltage, R = total resistance

Calculate the total resistance R of the circuit first.

R will be the sum of the 4ohm resistor and the resistance of the 5&9ohm parallel resistors. To find the resistance of the pair, you apply the “sum of inverses” rule:

R = 1/(1/5 + 1/9) = 3.21ohm

Now add the 4ohm resistor:
R = 3.21 + 4 = 7.21ohm

Now let’s calculate I = V/R:
Given values:
V = 6.0V
R = 7.21ohm
Plug in and solve for I:
I = 6.0/7.21

I = 0.83A
8 0
4 years ago
A car is traveling 20 m/s and slows down at a uniform rate. It stops in 6 seconds. How far has it traveled in this interval?
Scilla [17]

Answer:

Car travel a distance of 60.06 m in 6 sec

Explanation:

We have given initial velocity v = 20 m/sec

Time = 6 sec

As the car stops finally so final velocity v = 0

From the first equation of motion

v = u+at (as the car velocity is slows down means it is a case of deceleration)

So v = u-at

0=20-a\times 6

a=3.33m/sec^2

Now from second equation of motion s=ut-\frac{1}{2}at^2=20\times 6-\frac{1}{2}\times 3.33\times 6^2=60.06m

6 0
3 years ago
From 0 seconds to 4 seconds is the acceleration positive or negative?
Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
3 years ago
Based on your answer,what idea comes in to your mind?​
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Explanation:

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3 years ago
How does the electric field intensity vary with the increase of distance of the point from the centre of a charged conducting sp
Nataly_w [17]

Answer:

(i)  Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=q0qend

Since E is perpendicular to gaussian surface, angle betwee E is 0.

Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

So, E=4πε01r2q

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3 years ago
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