All categories

2 years ago

ولقد ائينا لقن أكمة أي أشگر ل ومن ي فإنما |

Physics

1 answer:

Ierofanga [76]2 years ago

3 0

ما هذا؟
هل لديك سؤال؟

You might be interested in

According to the article, in which TWO ways is lava similar to volcanic ash?

allochka39001 [22]

I don't see the article but i personally know that

-they both originate from volcanoes
-and ash comes from solidified lava clashing with rocks

7 0

3 years ago

That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

liraira [26]

Answer:

The answer is " $0.13562748$ "

Explanation:

Please find the complete question in the attached file.

Using formula:

$\bold{U_s=\frac{v^2}{rg}}$

Given:

$r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}$

put the value into the above-given formula:

$U_s= \frac{14.583^2}{160 \times 9.8}$

$= \frac{212.663889}{1568}\\\\=0.13562748$

3 0

2 years ago

Is displacement a fundermetal unit or derived unit.

balandron [24]

Answer:

Displacement is fundamental unit

8 0

2 years ago

Read 2 more answers

An engine performs 6400 j of work on a motorbike the motorbike and the rider have a combined mass of 200 kg if the bike started

spin [16.1K]

The work done by the engine is converted into kinetic energy of the motorbike+rider system:

$W=K=\frac{1}{2}mv^2$

where

W=6400 J is the work

m=200 kg is the mass of the system

v is the speed acquired by the motorbike

Rearranging the equation and substituting the numbers in, we find

$v=\sqrt{\frac{2W}{m}} =\sqrt{\frac{2(6400 J)}{200 kg}} =8 m/s$

4 0

2 years ago

Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False

kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

$\vec{L} = I \vec{\omega}$

where $I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2$ is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

$\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2}$ so $\vec{\omega} \neq 0$ unless $\vec{r}$ ║ $\vec{v}$ .

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

7 0

2 years ago