Answer:
hello your question is incomplete attached below is the missing diagram to the question and the detailed solution
Answer : principal stresses : 0.82 MPa, -33.492 MPa
shear stress = 17.157 MPa
∅ = 9.09 ≈ 10°
Explanation:
The principal stress ( б1 ) = 0.82 MPa
( б2 ) = -33.492 MPa
The shear stress = 17.157 MPa
∅ = 9.09 ≈ 10°
attached below is the detailed solution and the Mohr's circle
Answer:
e = 3.97*10^-4
Explanation:
1.8 mm = 0.0018 m
2.6*10^4 mm = 26 m
Elongation is The ratio between the stretched length and the original length.
e = L/L0
This is calculated with Hooke's law:
e = σ/E
Where
σ: normal stress
E: elastic constant
σ = P/A
Where
P: normal load
A: cross section
A = π/4 * d^2
Therefore:
e = P / (A * E)
e = 4 * P / (π * d^2 * E)
e = 4 * 290 / (π * 0.0018^2 * 207*10^9) = 3.97*10^-4
Answer:
The appropriate response is "Concatenation". A further explanation is given below.
Explanation:
- Two or much more strings are almost always concatenated besides space-saving purposes, and therefore could be acknowledged as either a single product.
- A straightforward example that demonstrates concatenation should be to figure out what it means. How and why that ends up making a term separate from several other phrases is that almost all the messages are stacked together without any open space between each one.
Answer:
The correct option is;
D. Electric meter
Explanation:
An electric meter is a metering device that is used for the measurement of the electric power consumption of an electrical powered tools, a living space or a building
Electric meter readings are used by electric utility company to sell electric power to consumers at a given rate such that it allows the electric utility company to receive payment for the total power supplied, and for the consumer to regulate the amount of power consumed
The electric meters are usually calibrated in kilowatt hour (kWh) and prepaid meter displays the amount of units of power bought, while post paid meters are usually read once each billing period which is usually one month.
Answer:
by principal stress theory
t = 20.226
by total strain theory
t = 20.36
Explanation:
given data
internal radius 
= 150 mm
pressure p = 80 MPa
yield strength = 300 MPa
poisson's ratio = 0.3
a) by principal stress theory
thickness can be obtained as t
t = ![r_{1}\left [ (\frac{\sigma _{y} +p}{\sigma _{y} - 0.5p})^{1/3}-1 \right ]](https://tex.z-dn.net/?f=%20r_%7B1%7D%5Cleft%20%5B%20%28%5Cfrac%7B%5Csigma%20_%7By%7D%20%2Bp%7D%7B%5Csigma%20_%7By%7D%20-%200.5p%7D%29%5E%7B1%2F3%7D-1%20%5Cright%20%5D)
t = = 150\left [ (\frac{300 +80}{300-0.5*80})^{1/3}-1 \right ]
t = 20.226
b) by total strain theory
m =
m = 
= 3.75
we know that
K = 
k = 1.13
1.13 = 
= 170.36 mm
t = -
t = 170.36 - 150
t = 20.36
