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Allisa [31]
3 years ago
6

A driver traveling in her 16-foot SUV at the speed limit of 30 mph was arrested for running a red light at 15th and Main, an int

ersection that is 60 feet wide. The driver claimed innocence, on the grounds that the traffic signals were not set properly. The yellow light was on for the standard 4 seconds. The SUV driver's reaction time is assumed to be 1.5 seconds. Comfortable deceleration is at a rate of 10 feet/second2. Did a dilemma zone exist on this intersection approach? If so, how long was it? Assume the vehicle must completely clear the intersection to avoid "running a red light." Yes, D 63 ft. 7.
Engineering
1 answer:
Lynna [10]3 years ago
4 0

Answer:

(a) Yes

(b) 102.8 ft

Explanation:

(a)First let convert mile per hour to feet per second

30 mph = 30 * 5280 / 3600 = 44 ft/s

The time it takes for this driver to decelerate comfortably to 0 speed is

t = v / a = 44 / 10 = 4.4 (s)

given that it also takes 1.5 seconds for the driver reaction, the total time she would need is 5.9 seconds. Therefore, if the yellow light was on for 4 seconds, that's not enough time and the dilemma zone would exist.

(b) At this rate the distance covered by the driver is

s = v_0t + \frac{at^2}{2}

s =44*1.5 + 44(4.4) - \frac{10*4.4^2}{2} = 162.8 (ft)

Since the intersection is only 60 feet wide, the dilemma zone must be

162.8 - 60 = 102.8 ft

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Which option identifies the next step in the following scenario?
Whitepunk [10]

Answer: The engineer will create a detailed sketch that labels all of the visual components.

Explanation:

It should be noted that the reverse engineering is required for the replacement and the modification of an existing product.

With regards to the question, the correct answer is option A "The engineer will create a detailed sketch that labels all of the visual components".

4 0
3 years ago
For the speed equation along centerline of a diffuser, calculate the fluid acceleration along the diffuser centerline as a funct
Marrrta [24]

Answer:

a = v\cdot \frac{dv}{dx}, v (x) = v_{in}\cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x \right]^{-1}, \frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1  \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}

Explanation:

Let suppose that fluid is incompressible and diffuser works at steady state. A diffuser reduces velocity at the expense of pressure, which can be modelled by using the Principle of Mass Conservation:

\dot m_{in} - \dot m_{out} = 0

\dot m_{in} = \dot m_{out}

\dot V_{in} = \dot V_{out}

v_{in} \cdot A_{in} = v_{out}\cdot A_{out}

The following relation are found:

\frac{v_{out}}{v_{in}} = \frac{A_{in}}{A_{out}}

The new relationship is determined by means of linear interpolation:

A (x) = A_{in} +\frac{A_{out}-A_{in}}{L}\cdot x

\frac{A(x)}{A_{in}} = 1 + \left(\frac{1}{L}\right)\cdot \left( \frac{A_{out}}{A_{in}}-1\right)\cdot x

After some algebraic manipulation, the following for the velocity as a function of position is obtained hereafter:

\frac{v_{in}}{v(x)} = 1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1\right) \cdot x

v(x) = \frac{v_{in}}{1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x}

v (x) = v_{in}\cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}}-1  \right)\cdot x \right]^{-1}

The acceleration can be calculated by using the following derivative:

a = v\cdot \frac{dv}{dx}

The derivative of the velocity in terms of position is:

\frac{dv}{dx} = -v_{in}\cdot \left(\frac{1}{L}\right) \cdot \left(\frac{v_{in}}{v_{out}}-1  \right) \cdot \left[1 + \left(\frac{1}{L}\right)\cdot \left(\frac{v_{in}}{v_{out}} -1 \right) \cdot x \right]^{-2}

The expression for acceleration is derived by replacing each variable and simplifying the resultant formula.

8 0
3 years ago
Read 2 more answers
ladders are not required to be inspected for visible defects prior to the first use of each work shift,and after any occuurrence
zaharov [31]

Answer:

The answer is False.

Explanation:

When it comes to occupational safety,<em> it is very important for ladders to be inspected by a qualified person before each use.</em> This is because ladders undergo conditions that impact their integrity while being in use. The inspection is also essential in order for the ladder to be timely replaced.

<u><em>Ladder accidents or ladder-related injuries happen every year.</em></u> Around 700 occupational deaths due to elevated fall from a ladder accounts for 15% of all occupational deaths. Misuse or damage ladders are often the reasons for this.

Thus, the answer in the above statement is False because ladders are required to be inspected for visible defects prior to the first use of each work shift and after any occurrence that could affect their safety.

4 0
3 years ago
In a brief report, discuss why we need various modes of transportation. How did they evolve? Discuss
Kitty [74]

Answer:

this is confusing

Explanation:

6 0
3 years ago
An aluminum electrical cable is 20 mm in diameter is covered by a plastic insulation (k = 1 W/m-k) of critical thickness. This w
Anastaziya [24]

Answer:

the heat loss from this insulated wire is less

Explanation:

Given data in question

diameter of cable (d)  =  20 mm

( K ) = 1 W/m-k

heat transfer coefficient (h) = 50 W/m²-K

To find out

the heat loss from this insulated wire

solution

we will find out thickness of wire

heat loss is depend on wire thickness also

we have given dia 20 mm

so radius will be d/2 = 20/ 2 = 10 mm

Now we find the critical thickness i.e.

critical thickness = K / heat transfer coefficient

critical thickness = 1 / 50 = 0.02 m i.e. 20 mm

now we can see that critical thickness is greater than radius 10 mm

so our rate of heat loss will be decreasing

so we can say our correct option is (a) less

5 0
3 years ago
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