Is c = 7 a solution to the inequality below? 3 < 9− c
2 answers:
You might be interested in
9514 1404 393
Answer:
- 7 forks
- 20 spoons
Step-by-step explanation:
Let x and y represent the numbers of forks and spoons made, respectively.
The cost of materials is ...
1.70x + 1.30y = 37.90
The revenue from sales is ...
5.60x + 5.40y = 147.20
You can solve these by any of your favorite methods. A graph is attached. It shows the solution is (x, y) = (7, 20).
They made 7 forks and 20 spoons.
_____
<em>Additional working out</em>
The equation coefficients are not "nice" multiples of each other, so elimination and substitution will require multiplying both equations by some numbers. If we're going to that trouble, we may as well use Cramer's Rule or a variation of the "cross multiplication method". The latter is relatively straightforward and can be easy to remember. It tells you the solution to ...
ax +by +c = 0
dx +ey +g = 0
is ...
1/(ae-db) = x/(bg-ey) = y/(cd-ga)
Here, that becomes ...
1/(1.70·5.40-5.60·1.30) = x/(1.30·(-147.20)-5.40·(-37.90))
= y/(-37.90·5.60-(-147.20·1.70))
1/1.9 = x/13.3 = y/38
x = 13.3/1.9 = 7 . . . number of forks
y = 38/1.9 = 20 . . . number of spoons
__
The above solution formula may be more easily remembered in terms of the cross-multiplication pattern that gives the method its name. When the coefficients are written in two rows of four, with the last being a repeat of the first:
- a b c a
- d e g d
each of the three denominators (of 1, x, and y) is the difference of products in adjacent columns, formed in an X fashion: ae-db, bg-ec, cd-ga. Note that the equations are written in "general" form, which is similar to "standard" form, but with all of the non-zero terms on the left of the equal sign. (This has the effect of changing the sign of the constants: 1.7x+1.3y=37.9 ⇒ 1.7x+1.3y-37.9=0)
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.
Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here