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How would you describe a food chain to someone who never thought about that idea before

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Explanation :

Formula used :

$\pi =CRT\\\\\pi=\frac{w}{M\times V}RT$

where,

$\pi$ = osmotic pressure = 0.745 torr = 0.000980 atm (1 atm = 760 torr)

C = concentration

R = solution constant = 0.0821 L.atm/mol.K

T = temperature = $27^oC=273+27=300K$

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution = 1.05 L

Now put all the given values in the above formula, we get:

$0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)$

$M=2.40\times 10^5g/mol$

Therefore, the molar mass of catalase is, $2.40\times 10^5g/mol$

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