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3 years ago

Select the correct answer.

Physics

2 answers:

Ludmilka [50]3 years ago

8 0

Answer:

Explanation:

Force has both direction and magnitude due to it being a vector quantity. Think of it this way--if I push you, what will happen to you?

Doesn't it depend on 1) how hard I pushed you, and 2) what direction I pushed you? Did I push you towards the wall? Towards a bed? How hard? Hard enough for you to fall?

arsen [322]3 years ago

5 0

Answer:

Explanation:

Force is a vector quantity. So, it has magnitude and direction which can also be describe as strength and direction

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A force of 5.0 N acts on a 15 kg body initially at rest. Compute the work done by the force in (a) the first, (b) the second, an

Leokris [45]

Answer:

(a) 0.833 j

(b) 2.497 j

(d) 4.995 watt

Explanation:

We have given force F = 5 N

Mass of the body m = 15 kg

So acceleration $a=\frac{F}{m}=\frac{5}{15}=0.333m/sec^2$

As the body starts from rest so initial velocity u = 0 m/sec

(a) From second equation of motion $s=ut+\frac{1}{2}at^2$

For t = 1 sec

$s=0\times 1+\frac{1}{2}\times 0.333\times 1^2=0.1666m$

We know that work done W =force × distance = 5×0.1666 =0.833 j

(b) For t = 2 sec

$s=0\times 2+\frac{1}{2}\times 0.333\times 2^2=0.666m$

We know that work done W =force × distance = 5×0.666 =3.33 j

So work done in second second = 3.33-0.833 = 2.497 j

$s=0\times 3+\frac{1}{2}\times 0.333\times 3^2=1.4985m$

We know that work done W =force × distance = 5×1.4985 =7.4925 j

So work done in third second = 7.4925 - 2.497 -0.833 = 4.1625 j

(d) Velocity at the end of third second v = u+at

So v = 0+0.333×3 = 0.999 m /sec

We know that power P = force × velocity

So power = 5× 0.999 = 4.995 watt

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drek231 [11]

Answer:

yabarrow

Explanation:

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Answer:

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Explanation:

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if the kinetic and potential energy in a system or equal to the potential energy increases what happens as a result

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Explanation:

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Answer:

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