i really need help! please hurry and answer this. i'll give you 5 stars and everything just please answer this as fast as you ca
n.
1 answer:
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Answer:
Explanation:
The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:
Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.
Also, we know that the centripetal force of an object describing a circular motion is given by:
Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.
Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:
Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So and
(Since
). Then, we get:
In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).
Answer:
-1748*10^N/C
Explanation:
See attached file
Answer:
(a) = 4.19 x
N, and its direction is towards
.
(b) It must be placed inside a hollow shell.
Explanation:
Let, = 165 kg,
= 465 kg,
= 60 kg, and the distance between
and
is 0.340 m.
(a) Since is placed midway between
and
, then its distance to both masses is 0.170 m.
From the Newton's law of universal gravitation,
F =
Where all variables have their usual meaning.
Then,
a. =
-
=
= 2.25 x N
=
= 6.44 x N
∴ = = 6.44 x
- 2.25 x
= 4.19 x N
The net force exerted by the two masses on the 60 kg object is 4.19 x N.
(ii) // = /
/ - /
/
= 6.44 x - 2.25 x
= 4.19 x N
(iii) The direction of the net force is to the right i.e towards .
(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.