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3 years ago

5

What occurs during stage one sleep

1 answer:

Mekhanik [1.2K]3 years ago

3 0

Answer:

Stage one of sleep, also known as the transitional phase, occurs when one finds themselves floating in and out of consciousness. During this NREM stage, you may be partially awake while your mind begins to drift off. This period of drowsiness eventually leads to a light sleep

Explanation:

i found it on google

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What makes a force a vector quantity

klasskru [66]

Answer:

A vector quantity is a quantity that has both magnitude and direction.

Explanation:

3 0

2 years ago

A 10.1 g bullet leaves the muzzle of a rifle with a speed of 425 m/s. What constant force is exerted on the bullet while it is t

PIT_PIT [208]

Answer

Force will be 1520.2604 N

Explanation:

We have given mass of the bullet m = 10.1 gram = 0.0101 kg

Distance S= 0.6 m

Final velocity v = 425 m/sec

Initial velocity u will be 0 m/sec

From third equation of motion $v^2=u^2+2as$

$425^2=0^2+2\times a\times 0.6$

$a=150520.833m/sec^2$

We know that force is given by F = ma

So force = 0.0101×150520.833 = 1520.2604 N

5 0

3 years ago

Bill steps off a 3.0-m-high diving board and drops to the water below. At the same time, Ted jumps upward with a speed of 4.2 m/

Pani-rosa [81]

Answer:

equation of motion for Bill is

$y(t) = 4.9t^2$

equation of motion for Ted is

$y(t) = 2 + (-4.2)(t) + 4.9t^2$

Explanation:

Taking downward position positive and upward position negative

g = 9.8 m/s^2

equation of motion for Bill is

$y(t) = y_0 +v_0 t +\frac{1}{2}gt^2$

$y(t) = 0 + 0(t) +\frac{1}{2}gt^2$

$y(t) = \frac{1}{2}\times (9.8t)^2$

$y(t) = 4.9t^2$

equation of motion for Ted is

$y_0 = 2m -1m = 2m$

$y_0 = -4.2 m/s$

$y(t) = y_0 +v_0 t +\frac{1}{2}gt^2$

$y(t) = 2 + (-4.2)(t) +\frac{1}{2}gt^2$

$y(t) = 2 + (-4.2)(t) +\frac{1}{2}\times (9.8t)^2$

$y(t) = 2 + (-4.2)(t) + 4.9t^2$

8 0

3 years ago

Read 2 more answers

1.48 Assume that the air volume in a small automobile tire is constant and equal to the volume between two concentric cylinders

ICE Princess25 [194]

Answer:

a) 0.018 kg

b) 262 kPa

Explanation:

The volume of the concentric cylinders would be:

V = π/4 * h * (D^2 - d^2)

V = π/4 * 13 * (52^2 - 33^2) = 16500 cm^3 = 0.0165 m^3

The state equation of gases:

p * V = m * R * T

Rearranging:

m = (p * V) / (R * T)

R is 287 J/(kg * K) for air

25 C = 298 K

m0 = 202000 * 0.0165 / (287 * 298) = 0.039 kg

After pumping more air the volume remains about the same, but temperature and pressure change.

30 C = 303 K

m1 = 303000 * 0.0165 / (287 * 303) = 0.057 kg

The mass that was added is

m1 - m0 = 0.057 - 0.039 = 0.018 kg

If that air is cooled to 0 C

0 C is 273 K

p = m * R * T / V

p = 0.057 * 278 * 273 / 0.0165 = 262000 Pa = 262 kPa

3 0

2 years ago

What is the question at the center of the situation discussed in the video?

VashaNatasha [74]

Answer:

44

Explanation:

jk you didnt share the video lol

7 0

3 years ago