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Tema [17]
3 years ago
7

What newton equal to in terms of units of mass and acceleration

Physics
2 answers:
Korvikt [17]3 years ago
4 0
This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's<span> Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is </span>equal<span> to the </span>mass<span>of the object multiplied by the </span>acceleration<span> of the object.</span>
Effectus [21]3 years ago
4 0
One 'Newton' is the amount of force that will accelerate 1 kilogram of mass at the rate of 1 meter per second-squared. Its units are kg-m/s^2. One Newton is equivalent to about 3.6 ounces of force. 1pound = about 4.445 N.
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An object weighing 4 newtons swings on the end of a string as a simple pendulum. At the bottom of the swing, the tension in the
Anit [1.1K]

Answer:

(B) 0.5 g

Explanation:

Newton's second law says ∑  F i = m a .

the rate of change in momentum of a body is proportional to the force applied on the body.

f∝ma

f=kma

were k is constant and equal to 1

The centripetal acceleration is an acceleration.

the tension on the swing and object weight goes to the left hand side while the centripetal acceleration goes to the right handside

At the bottom of the swing, ΣF = FT – mg = mac;

notice that the tension in the swing is 1.5 times the weight of the object

we can write

1.5mg – mg = mac,

0.5mg = mac

0.5 g=ac

8 0
3 years ago
Read 2 more answers
The magnetic field at the center of a 1.40-cm-diameter loop is 2.50 mT . PART A) What is the current in the loop?
NISA [10]

Explanation:

It is given that,

Diameter of loop, d = 1.4 cm

Radius of loop, r = 0.7 cm = 0.007 m

Magnetic field, B=2.5\ mT=2.5\times 10^{-3}\ T

(A) Magnetic field of a current loop is given by :

B=\dfrac{\mu_oI}{2r}

I is the current in the loop

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.5\times 10^{-3}\times 0.007}{4\pi \times 10^{-7}}

I = 27.85 A

(B) Magnetic field at a distance r from a wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 27.85}{2\pi \times 2.5\times 10^{-3}}

r = 0.00222 m

r=2.2\times 10^{-3}\ m

Hence, this is the required solution.

3 0
3 years ago
The aluminum atom______electrons to form an ion.<br> The ion that is formed is______.
Alchen [17]

The aluminum atom_loses_____electrons to form an ion.

The ion that is formed is_Al³⁺_____.

aluminium has the electronic configuration as 1s² 2s² 2p⁶ 3s² 3p¹

from the electronic configuration , we see that aluminium can attain stability by losing 3 electrons from outer shell.

after losing 3 electrons , the ion formed is given as Al³⁺

hence the correct options to fill in the blanks are lose  and Al³⁺


3 0
3 years ago
Read 2 more answers
Would it be better to collide head-on with an identical car traveling at the same speed or collide with a stationary brick wall?
attashe74 [19]
It makes no difference. The momentum of either car goes to zero in both cases.
6 0
3 years ago
A sprinter with a mass of 80 kg accelerates from 0 m/s to 9 m/s in 3 s. What is the runner's acceleration?
sertanlavr [38]
Acceleration = (change in speed) / (time for the change) = 9/3 = <em>3 m/s²</em> .

His mass makes no difference.
5 0
3 years ago
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