Yes what the other person said can I plz get an thanks
41.38 % Mg
55.17 % O
3.45 % H
Explanation:
What is the percent composition of magnesium hydroxide Mg(OH)₂?
To find the percent composition we follow the next algorithm.
First we calculate the molar mass of Mg(OH)₂:
molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2
molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole
Now we devise the next reasoning:
if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H
then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H
X = (100 × 24) / 58 = 41.38 % Mg
X = (100 × 32) / 58 = 55.17 % O
X = (100 × 2) / 58 = 3.45 % H
Learn more about:
percent composition
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The answer is option C 7.60 M
The reaction is not at equilibrium and it is in the forward direction.
a.
Given,
[N₂] = 0.910 mol / L
[H₂] = 0.3 mol / L
[NH₃] = 0.0081 mol / L
K = 9.83 x 10⁻²
The balanced chemical equation for the given reaction is,
N₂(g) + 3H₂(g) ⇄ 2NH₃(g)
The formula of equilibrium constant is given by,
K = [NH₃]² / [N₂] [H₂]²
9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]
⇒9.83 x 10⁻² = (0.00006561) / (0.0819)
⇒9.83 x 10⁻² = 0.0008010989
⇒0.00983 = 0.0008010989
LHS ≠ RHS
Hence, the reaction is not at equilibrium.
b.
The reaction is in forward direction.
Learn more about direction of the reaction from the link given below.
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Radioactive isotope, also called radioisotope, radionuclide, or radioactive nuclide, any of several species of the same chemical element with different masses whose nuclei are unstable and dissipate excess energy by spontaneously emitting radiation in the form of alpha, beta, and gamma rays.
