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2 years ago

PLEASE HELP!!!!!!!

Chemistry

1 answer:

Keith_Richards [23]2 years ago

6 0

Answer: The gas generated by two antacid tablets has a smaller volume.

Explanation:

Since the antiacid is the limiting reagent, we know that the more tablets there are, the more gas there will be.

This means that there will be more gas generated by the four antiacid tablets when compared to the two antiacid tablets, which gives us that the gas generated by the two antiacid tablets has a smaller volume.

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tankabanditka [31]

Answer:

True

Explanation:

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3 years ago

At the end of the reaction you washed the chemicals into a beaker using water. Why was it OK to use water to do this if Grignard

lesya692 [45]

Answer: water could be used to wash it since the reaction has ended.

Explanation:

There will be no reaction of water with the Grignard reagent since the reaction has ended, as it is well known that water is a universal solvent for washing of glasswares after experiments but if it is during the reaction it will be more advisable to rinse with alcohol to enhance more accuracy during the experiment

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3 years ago

How does the law of conservation of matter apply to chemical equations?

Tasya [4]

Answer: option D.

The total number of atoms of each element on both sides of the

equation must be the same.

Explanation:

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4 years ago

Difference between Rapid and spontaneous composition

Over [174]

Answer:

spontaneous composition is the ingnition

of the substance due to the repid oxidation of its on material.

There is no requirement of heat of external sources.

Rapid composition on the other hand release large amount of heat and light energy.

Explosion and the firecracker is the best example of Rapid composition.

3 0

3 years ago

A mixture containing 20 mole % butane, 35 mole % pentane and rest

notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

$Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB$

Whereas $y$ accounts for the fractions at the outlet distillate and $x$ for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

$0.9=\frac{y_bD}{z_bF}$

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

$y_bD=0.9*z_bF=0.9*0.2*100mol=18mol$

The total distillate flow:

$y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol$

And the total bottoms flow:

$F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol$

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

$x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025$

Then, the molar fraction of pentane and hexane:

$x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422$

$x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553$

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

8 0

3 years ago

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