the reaction is
2NO(g) + 2H2(g) <—> N2(g) + 2H2O (g)
Kc = [N2] [ H2O]^2 / [NO]^2 [ H2]^2
Given
moles of NO = 0.124 therefore [NO] = moles /volume = 0.124 /2 = 0.062
moles of H2 = 0.0240 , therefore [H2] = moles / volume = 0.0240 / 2 = 0.012
moles of N2 = 0.0380 , therefore [N2] = moles / volume = 0.0380 / 2 = 0.019
moles of H2O = 0.0276 , therefore [H2O] = moles / volume = 0.0276 / 2 = 0.0138
Kc = (0.019) ( 0.0138)^2 / (0.062)^2 ( 0.012)^2 = 6.54
Answer:
True
Explanation:
Water boils at 373 kelvins. ... Absolute zero is –273.15° C or –459.67° F. The "size" of a one degree change in temperature is exactly the same in the Celsius and Kelvin scales, so the freezing point of water is at a temperature of 273.15 kelvins (that is, 273.15 degrees above absolute zero
B.
There is no covalent bonds in pure H2O. Only hydrogen
Answer:All the above
Explanation:
Non-ideal solutions are those solutions which do not obey Raoult's law in any conditions.
The molecular interactions of two components that is solute and solvent are different.
If there are two components A and B then the molecular interaction between A-A,B-B would be different from the molecular interactions in A-B .
The enthalpy of mixing and volume of mixing for non-ideal solutions have non zero values.
Enthalpy of mixing can be negative or positive in case of non-ideal solutions. If the enthalpy of mixing is negative so energy has been released upon mixing the two components and if enthalpy of mixing is positive then energy is absorbed upon mixing the two components.
Non-ideal solutions are simply those solutions which are not ideal hence they should not be having the characterstics of ideal solutions.
For ideal solutions the molecular interactions between the two components are equal.
So the molecular interaction between A-A,B-B would be equal to the molecular interaction between A-B. Also the enthalpy of mixing and volume of mixing for ideal solutions are zero hence all the statements provided here are correctly charactersing non-ideal solutions.
