Answer:
B. A method of obtaining an emission spectrum from a sample
Explanation:
Answer:
its b there circle e not oval
Explanation:
Problem 2
You start out with 216 ugrams of Fermium - 253. After 3 days, you will have 1/2 as much. 108 ugrams is what you have.
Another 3 days goes by. You started with 108 ugrams. That gets cut in 1/2 again. Now you have 54 ugrams.
Finally another 3 days goes by. You started with 54 ugrams. you now have 1/2 as much which would be 27 ugrams
#days Amount in micrograms
0 216
3 108
6 54
9 27
Problem One
You are using Nitrogen as your base example. The first thing you should do is fill in the table. Then you should try and make some rules. You need the rules in case the exam you are preparing for picks a different element to talk about these bond tendencies. In any event, it's handy to think this way.
<em><u>Table</u></em>
Bond Energy Kj/Mol Bond Length pico meters
N - N 167 145
N=N 418 125
N≡N 942 110
<em><u>Rules</u></em>
As the number of bonds INCREASES, the energy contained in the bond goes UP
As the number of bonds INCREASES, the length of the bond goes DOWN.
Molar mass HCl = 1.01 + 35.45 => 36.46 g/mol
number of moles:
mass HCl / molar mass
9.63 / 36.46 => 0.2641 moles of HCl
Therefore:
M = moles / Volume ( in liters )
M = 0.2641 / 1.5
M = 0.1760 mol/L⁻¹
Whenever I have tests like these, I make a quizlet with each part zoomed in and then answer it that way.
