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sasho [114]
3 years ago
8

2.3*10^14 and 5.4*10^-3

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

The first one would be 2.3e+14

and the second would be 0.0054

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Complete this neutralization equation:<br> H2SO4 + Al(OH)3
elena-s [515]

Answer:

H2SO4 + Al(OH)3 = Al2(SO4)3 + H2O

Explanation:

4 0
3 years ago
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
3 years ago
What is the most soluble salt of the following set? What is the most soluble salt of the following set?
DiKsa [7]

Answer:

(c) AgCN\ (K_{sp} =6.0\times 10^{-17})

Explanation:

The solubility product of a solid is the amount of solid dissociates into its respective ions in the solution. Thus more the value of the Ksp, the more is the salt soluble in the solvent.

So,  Given that:-

Sn(OH)_2\ (K_{sp} =1.6\times 10^{-19})

Al(OH)_3\ (K_{sp} =1.9\times 10^{-33})

AgCN\ (K_{sp} =6.0\times 10^{-17})

Fe(OH)_3\ (K_{sp} =2.6\times 10^{-39})

The salt having highest value of Ksp is AgCN. So, it is most soluble.

4 0
3 years ago
You HAVE 1L of 2.0 mol/L HCI. You want to dilute the solution to a concentration of 0.1 mol/L. What volume of the new solution (
enot [183]
<h3>Given:</h3>

M₁ = 2.0 mol/L

V₁ = 1 L

M₂ = 0.1 mol/L

<h3>Required:</h3>

V₂

<h3>Solution:</h3>

M₁V₁ = M₂V₂

V₂ = M₁V₁ / M₂

V₂ = (2.0 mol/L)(1 L) / (0.1 L)

<u>V₂ = 20 L</u>

Therefore, the volume of the new solution will be 20 L.

#ILoveChemistry

#ILoveYouShaina

7 0
3 years ago
Read 2 more answers
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
Alja [10]

The electron-group arrangement of CO₃²⁻ is trigonal planar. The molecular shape is trigonal planar, and the ideal bond angle(s) is CO₃²⁻ is 120°

<h3>What is the molecular geometry of a compound?</h3>

The position of the compound's electrons and nuclei can be seen in the molecular geometry. It demonstrates how the form of the complex is created by the interaction of electrons and nuclei.

Here, according to the VSEPR  theory, the shape of the carbonate ion is trigonal planar. The carbon will be in the center.

Thus, the electron-group arrangement and the shape of the carbonate ion are trigonal planar. The bond angle will be 120°.

To learn more about molecular geometry, refer to the link:

brainly.com/question/16178099

#SPJ4

6 0
1 year ago
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