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2 years ago

How many carbon atoms are there in one molecule of CH3FO?

Chemistry

1 answer:

Vlad1618 [11]2 years ago

8 0

Answer:

Brainliest pls

Explanation:

1 mole of a substance contains Avagadro’s number of particles,

i.e. 6.023*10^23

By unitary method,

5 moles of oxygen contains 5 times the Avagadro’s number of particles

i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.

Now, the further answer depends on what particles the question concentrates on.

If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.

therefore, 5 moles of oxygen has 6.023*10^24 atoms.

If number of molecules asked, the above answer is directly written...

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Enter your answer in the provided box. To make use of an ionic hydrate for storing solar energy, you place 409.0 kg of sodium su

alex41 [277]

Answer:

409.0 kg of sodium sulfate decahydrate will produce 4.49×10⁵ kJ

of heat energy.

Explanation:

CHECK THE COMPLETE QUESTION BELOW

To make use of an ionic hydrate for storing solar energy, you place 409.0 kg of sodium sulfate decahydrate on your house roof. Assuming complete reaction and 100% efficiency of heat transfer, how much heat (in kJ) is released to your house at night? Note that sodium sulfate decahydrate will transfer 354 kJ/mol

EXPLANATION

Here we were asked to calculate the amount of heat will be generated by 409.0 kg of sodium sulfate decahydrate at night assuming there Isa complete reaction and 100% efficiency of heat transfer in the process

The molecular weight of sodium sulfate decahydrate (H₂₀Na₂O₁₄S) is needed here, so it must be firstly calculated.

The molecular weight of sodium sulfate decahydrate (H₂₀Na₂O₁₄S)

( 1*20) + (22.98*2) + (16*14)+ (32*14)= 322.186 g/mol.

Thus 409.0 kg of H₂₀Na₂O₁₄S will have a value which is equivalent to = (409000g)/(322.186 g/mol.)

=1269.453mol of H₂₀Na₂O₁₄S.

But it was stated in the the question that per mole of H₂₀Na₂O₁₄S will transfer 354 kJ heat.

Therefore, 1269.453mol will transfer 1269.453× 354 kJ = 4.49×10⁵ kJ of heat.

Hence, 409.0 kg of sodium sulfate decahydrate will produce

4.49×10⁵ kJ of heat energy.

6 0

3 years ago

A sample of oxygen has a volume of 128 milliliter at a pressure of 500.0 mmhg calculate the volume this sample would occupy at s

leva [86]

Answer:

84.2mL

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 128mL

Initial pressure (P1) = 500mmHg

Final pressure (P2) = stp = 760mmHg

Final volume (V2) =..?

Thus, the new volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

500 x 128 = 760 x V2

Divide both side by 760

V2 = (500 x 128)/760

V2 = 84.2mL

Therefore, the new volume of the gas is 84.2mL

4 0

4 years ago

Give the number of significant figures in this number: 7.8 x 10¹²

denis-greek [22]

The number is written in scientific notation.

The significant figures are the numbers known precisely plus 1 digit that is uncertain.

When the numbers are expressed in scientific notation all the digits before 10^n are significant.

So, 7 and 8 are significant figures and the answer is that the number of significant figures is 2.

Answer: 2

8 0

4 years ago

An orbital is best defined as

kaheart [24]

The answer is the most probable location of electrons in an atom

8 0

2 years ago

During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What

kvv77 [185]

Answer:

8.70 liters

Explanation:

3O₂+ 4Al → 2AI₂O₃

First we convert 36.12 g of AI₂O₃ into moles, using its molar mass:

36.12 g ÷ 101.96 g/mol = 0.354 mol AI₂O₃

Then we convert AI₂O₃ moles into O₂ moles, using the stoichiometric coefficients of the reaction:

0.354 mol AI₂O₃ * $\frac{3molO_2}{2molAl_2O_3}$ = 0.531 mol O₂

We can now use the PV=nRT equation to calculate the volume, V:

1.4 atm * V = 0.531 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 280.0 K

V = 8.708 L

5 0

3 years ago