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1 year ago

How many carbon atoms are there in one molecule of CH3FO?

Chemistry

1 answer:

Vlad1618 [11]1 year ago

8 0

Answer:

Brainliest pls

Explanation:

1 mole of a substance contains Avagadro’s number of particles,

i.e. 6.023*10^23

By unitary method,

5 moles of oxygen contains 5 times the Avagadro’s number of particles

i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.

Now, the further answer depends on what particles the question concentrates on.

If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.

therefore, 5 moles of oxygen has 6.023*10^24 atoms.

If number of molecules asked, the above answer is directly written...

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During science class billy used litmus paper to determine the ph of an unknown liquid. the blue litmus paper turns red but there

denis-greek [22]

He was testing an acid. So your answer will be C.

Hope this helps!

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3 years ago

If you have 1.005 x 1024 molecules of Ca(OH)2 how many atoms do you have? Moles? Grams?

ira [324]

Answer:

5.025x10²⁴ atoms

1.6686 moles

123.63 g

Explanation:

In one Ca(OH)₂ molecule, there are 5 atoms (1 Ca, 2 O and 2 H). This means that in 1.005x10²⁴ Ca(OH)₂ molecules, there are (5 * 1.005x10²⁴) 5.025x10²⁴ atoms.

To convert molecules into moles, we use Avogadro's number:

1.005x10²⁴ molecules * $\frac{1mol}{6.023*10^{23}molecules}$ = 1.6686 moles

Finally, we convert moles into grams using the molar mass of Ca(OH)₂:

1.6686 moles * 74.093 g/mol = 123.63 g

4 0

2 years ago

The Earth is approxiamately 1.5 X108km from the sun. How many minutes does

Roman55 [17]

Answer:

8 mins and 20 seconds i think

Explanation:

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2 years ago

At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s

Shalnov [3]

Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = 0.0632

t = time taken for the process = ?

$[A_o]$ = initial amount or concentration of the reactant = 1.28 M

$[A]$ = amount or concentration left time 't' = $1.28\times \frac{17}{100}=0.2176M$

Now put all the given values in above equation, we get:

$0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}$

$t=28s$

Therefore, the time taken for the reaction is, 28 s.

8 0

2 years ago

Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou

lesya [120]

First, let's compute the number of moles in the system assuming ideal gas behavior.

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol = 48.74 L

3 0

3 years ago