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algol [13]
2 years ago
10

If 70 mL of a 0.4 M Ba(NO3)2 solution is mixed with excess amount of a Na2CO3 solution, what is the theoretical yield of the pre

cipitate
Chemistry
1 answer:
Sindrei [870]2 years ago
7 0

The theoretical yield of BaCO3 is 5.5

<h3>What is theoretical yield?</h3>

The theoretical yield is the yield calculated from the stoichiometry of the reaction. The equation of the reaction is;

Ba(NO3)2(aq) + Na2CO3 (aq) ------> BaCO3(s) + 2NaNO3(aq)

Number of moles of limiting reactant: 0.4 M × 70/1000 = 0.028 moles

Since the reaction is 1:1,om;y 1 mole of BaCO3 is formed. Hence, mass of BaCO3 = 0.028 moles × 197 g/mol = 5.5g

Learn more about theoretical yield: brainly.com/question/2506978

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vovangra [49]

Answer:

Here's what I get  

Explanation:

1. Balanced equation

HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻

(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)

2. Mechanism

HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻

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At the same time as the Q-H bond starts to form, the C-Br bond starts to break.

At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.

As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).

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See the diagram below.

 

8 0
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4 0
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