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algol [13]
2 years ago
10

If 70 mL of a 0.4 M Ba(NO3)2 solution is mixed with excess amount of a Na2CO3 solution, what is the theoretical yield of the pre

cipitate
Chemistry
1 answer:
Sindrei [870]2 years ago
7 0

The theoretical yield of BaCO3 is 5.5

<h3>What is theoretical yield?</h3>

The theoretical yield is the yield calculated from the stoichiometry of the reaction. The equation of the reaction is;

Ba(NO3)2(aq) + Na2CO3 (aq) ------> BaCO3(s) + 2NaNO3(aq)

Number of moles of limiting reactant: 0.4 M × 70/1000 = 0.028 moles

Since the reaction is 1:1,om;y 1 mole of BaCO3 is formed. Hence, mass of BaCO3 = 0.028 moles × 197 g/mol = 5.5g

Learn more about theoretical yield: brainly.com/question/2506978

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Explanation:

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For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
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Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

x = mass extracted

m = total mass of solute

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Vo = volume of organic layer

Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

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So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then  

r = m(0.382)^n.

If n = 7,

r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

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After seven extractions, 75 mg (99.999 %) of the solute will be extracted.

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How many meters did a car travel if it went 65mi/hr for 4.5 hours?
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Answer:

292.5

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