All categories

2 years ago

If 50. 75 g of a gas occupies 10. 0 l at stp, 129. 3 g of the gas will occupy ________ l at stp.

Chemistry

1 answer:

NeX [460]2 years ago

8 0

22.4L

of any gas contains 1 mol of that gas.

50.75g/10L*22.4L/1 mol= 113.68g/mol- this is the mole weight of your gas

1 mol/113.68g*129.3g=1.137403 mol

Set up a ratio

1.137403mol/x L=1 mol/22.4 L

X=25.477827L, or with sig figs, x=25.5L

You might be interested in

When a strong acid is titrated with a strong base using phenolphthalein, the color changes suddenly at the end point. The color

larisa86 [58]

Answer:

Keto - enol tautomerism

Explanation:

Phenolphthalein is an organic molecule (formula: C20H14O4), which is used in to determine the final volume in an acid-base titration, this is, as the molecule changes from one to another color, depending on the Ph of the solution (in acids solution, the molecule remains colorless, while in basics solutions it remains pink) :

The molecule of phenolphthalein is a week acid, which losses a proton (H+) when it´s in solution: the undissociated molecule is colorless, while the correspondent anion (without a H+) is pink. This may be simplified with the following reaction:

H₃In⁺ ⇄ H₂In (colorless) ⇄ In⁻² (pink) ⇄ In(OH) ⁻³

- When adding a base (for example, NaOH) to phenolphthalein (initially, a colorless solution), molecule losses one H⁺ and we obtain In⁻², which is pink

- When adding an acid, the original structured is recovered, so color turns from pink to colorless

This change color is not only explained with adding an acid or a base, but also with phenolphthalein structure, that leads to a keto-enol tautomerism: as molecule has 2 hydroxyl groups (- OH) and 1 carbonyl group (C = O), compounds with this structure have an equilibrium between both groups:

R1 = C H– OH ⇄ R1 – C = O

With this change, phenolphthalein structure changes and hence, color solution changes as well

4 0

3 years ago

Which graph is an exponential growth model?<br> A<br> B<br> C

gtnhenbr [62]

A the first one represents an exponential growth chart

5 0

3 years ago

Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of

GarryVolchara [31]

The given question is incomplete. The complete question is :

Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of carbon dioxide and argon. The partial pressure of carbon dioxide is 0.080 atm and the partial pressure of argon is 0.24 atm. What is the total pressure of the mixture.

Answer: 0.32 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_{CO_2}+p_{Ar}$

Given : $p_{total}$ =total pressure of gases = ?

$p_{CO_2}$ = partial pressure of carbon dioxide = 0.080 atm

$p_{Ar}$ = partial pressure of argon = 0.24 atm

putting in the values we get:

$p_{total}=0.080atm+0.24atm$

$p_{total}=0.32atm$

Thus the total pressure of the gases is 0.32 atm

8 0

3 years ago

Suppose you need 0.12L of a 0.13M solution of NiCl2, but all you have is a solution that is a solution that is 0.23M. What volum

topjm [15]

- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

$M_aV_a= M_bV_b$

The initial molarity (concentration) $M_a =$ 0.13 M

The initial volume $V_a$ = 0.12 L

The desired molarity (concentration) $M_b$ = 0.23 M

The volume of the desired solution $V_b$ = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

Learn more about molarity here:

brainly.com/question/26873446

#SPJ4

3 0

2 years ago

A student mixes 40. Ml of 0. 10mhbr(aq) with 60. Ml of 0. 10mkoh(aq) at 25°c. What is the [oh−] of the resulting solution?

diamong [38]

After the complete neutralization reaction occurs, excess hydroxide ion is left unreacted the hydroxide ion of the resulting solution, [OH-] is 0.02 M.

<h3>What is the concentration of the hydroxide ion, [OH-]?</h3>

The hydroxide ion concentration is the amount in moles of hydroxide ion in a solution.

The hydroxide ion concentration is written as [OH-].

The equation of the reaction is given below:

1 mole of HBr reacts with 1 mole of KOH

Moles of HBr = 40 mL × 0.1 M = 4 mm moles

Moles of KOH = 60 mL × 0.1 M = 6 m moles

Moles of [OH-] = 6 - 4 = 2 m moles

Volume of solution = 100 mL

$[OH-] = \dfrac{2m\; moles}{100\; mL} = 0.02 M$

Thus, the concentration of the hydroxide ion, [OH-] is 0.02 M.

Learn more about hydroxide ion

brainly.com/question/25883474

#SPJ4

3 0

2 years ago