Answer:
Yup! The answer is 50 J/g* °C
Explanation:
I also took the test but I know how to work out the problem for anyone who wants to know how to solve it.
Remember the formula q = m*C*ΔT
m = the mass in grams
C = the specific heat Capacity
ΔT = change in time
q = amount of energy
So, find out what was given and what we need to look for:
m = 40 g
C = ?
ΔT = we're heating up (the temperature increases) a chemical so it needs to be a positive number. 25 - 10 = 15 °C
q = 30000 Joules
Now, set up the equation:
q = m*C*ΔT
30000 = 40 * C * 15
Multiply 40 and 15 to get 600:
30000 = 600 * C
Divide both sides by 600 to get C by itself (plug this into your calculator):
30000/600 = 600 * C/600
You are left with 50 = C
Now, you just need to plug in the units to get B. 50 J/g* °C
I hope I helped clear up any confusion! :D
You know you can add comments right!!! <span />
Test tubes heat small amounts of liquids while boiling tube boils liquids
Answer:
680 g/m is the molar mass for the unknown, non electrolyte, compound.
Explanation:
Let's apply the formula for osmotic pressure
π = Molarity . R . T
T = T° absolute (in K)
R = Universal constant gases
π = Pressure
Molarity = mol/L
As units of R are L.atm/mol.K, we have to convert the mmHg to atm
760 mmHg is 1 atm
28.1 mmHg is (28.1 .1)/760 = 0.0369 atm
0.0369 atm = M . 0.082 L.atm/mol.K . 293K
(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M
0.0015 mol/L = Molarity
This data means the mol of solute in 1L, but we have 100mL so
Molarity . volume = mol
0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole
The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m
