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meriva
2 years ago
13

If 50. 75 g of a gas occupies 10. 0 l at stp, 129. 3 g of the gas will occupy ________ l at stp.

Chemistry
1 answer:
NeX [460]2 years ago
8 0

22.4L

of any gas contains 1 mol of that gas.

50.75g/10L*22.4L/1 mol= 113.68g/mol- this is the mole weight of your gas

1 mol/113.68g*129.3g=1.137403 mol

Set up a ratio

1.137403mol/x L=1 mol/22.4 L

X=25.477827L, or with sig figs, x=25.5L

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*finished the test its B* In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 3
Illusion [34]

Answer:

Yup! The answer is 50 J/g* °C

Explanation:

I also took the test but I know how to work out the problem for anyone who wants to know how to solve it.

Remember the formula q = m*C*ΔT

m = the mass in grams

C = the specific heat Capacity

ΔT = change in time

q = amount of energy

So, find out what was given and what we need to look for:

m = 40 g

C = ?

ΔT = we're heating up (the temperature increases) a chemical so it needs to be a positive number. 25 - 10 = 15 °C

q = 30000 Joules

Now, set up the equation:

q = m*C*ΔT

30000 = 40 * C * 15

Multiply 40 and 15 to get 600:

30000 = 600 * C

Divide both sides by 600 to get C by itself (plug this into your calculator):

30000/600 = 600 * C/600

You are left with 50 = C

Now, you just need to plug in the units to get B. 50 J/g* °C

I hope I helped clear up any confusion! :D

8 0
2 years ago
Weigh out enough LB Agar to make 250 mL of agar solution and add to beaker.
a_sh-v [17]

Answer:

25lb 567.m

Explanation:

4 0
2 years ago
False answer it's F**** wrong
Aliun [14]
You know you can add comments right!!!  <span />
8 0
3 years ago
What is the difference between test tube and boiling tube​
mixer [17]

Test tubes heat small amounts of liquids while boiling tube boils liquids

5 0
2 years ago
0.102 g of an unknown(non electrolyte) compound is dissolved in enough water to make 100. mL of a solution and has an osmotic pr
Leni [432]

Answer:

680 g/m is the molar mass for the unknown, non electrolyte, compound.

Explanation:

Let's apply the formula for osmotic pressure

π = Molarity . R . T

T = T° absolute (in K)

R = Universal constant gases

π = Pressure

Molarity = mol/L

As units of R are  L.atm/mol.K, we have to convert the mmHg to atm

760 mmHg  is 1 atm

28.1 mmHg is (28.1  .1)/760 = 0.0369 atm

0.0369 atm = M . 0.082 L.atm/mol.K . 293K

(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M

0.0015 mol/L = Molarity

This data means the mol of solute in 1L, but we have 100mL so

Molarity . volume = mol

0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole

The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m

4 0
3 years ago
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