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Alexxandr [17]
3 years ago
5

Find the common difference of the sequence shown.

Mathematics
2 answers:
Vinvika [58]3 years ago
5 0
The sequence is n/6. (:
Dafna1 [17]3 years ago
4 0
I believe it is 1/3 

Hope I helped
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CP is equal to 200 SP is equal to 100 find the profit or loss​
ioda

Answer:

100

Step-by-step explanation:

if SP>CP,

It is profit [SP - CP = Profit]

if CP>SP,

It is loss   [CP - SP = Loss]

Here in the question CP>SP so,

loss = CP - SP

       =200 - 100

       = 100

5 0
2 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Different hotels in a certain area are randomly selected, and their ratings and prices were obtained online. Using technology, w
mash [69]

Answer:

Option C) The symbol y represents the predicted value of price.

Step-by-step explanation:

We are given the following in the question:

We find a regression equation with x representing the ratings and y representing price.

The equation has a slope of 130 and a y-intercept of 350.

Comparing with the slope intercept form:

y = mx + c\\\text{where m is the slope and c is the y intercept}

Thus, we can write the equation as:

y = 130x + 350

Here, y is the predicted variable that is the price, c is the price of hotel when a rating of 0 is given.

Thus, symbol y represents:

C) The symbol y represents the predicted value of price.

5 0
3 years ago
Kyle divided two numbers in scientific notation using the interactive calculator and found a solution of 3.5E4. If the numerator
Maru [420]

Answer:

a=2, b=5

Step-by-step explanation:

Let

n -----> the denominator

we have

3.5*10^4=\frac{7*10^9}{n}

Solve for n

That means -----> isolate the variable n

Multiply by n both sides

3.5*10^4(n)=7*10^9

Divide by 3.5*10^4 both sides

n=\frac{7*10^9}{3.5*10^4}=(\frac{7}{3.5})(\frac{10^9}{10^4})=2*10^5

therefore

a=2, b=5

5 0
3 years ago
Read 2 more answers
Anything will help please
svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

8 0
2 years ago
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