Answer:
1.549 m
Explanation:
Given:
The radius of the circular board, r = 2 m
The probability of hitting the red is given as 0.6
Now, this probability of hitting the red can be conclude as
0.6 = (Area of red)/ (Total area of the board)
Total area of the board = πr² = π × 2²
let the radius of the red area be R
thus, area of red circle, = πR²
on substituting the value of the area, we have
0.6 = (πR²)/ (π × 2²)
or
R² = 2.4
or
R = 1.549 m
Thus, the radius of the red circle is 1.549 m
 
        
             
        
        
        
Answer:
8 units
Explanation:
F=(k*q1*q2)/(r^2)
K is a constant, q1 is charge of 1, q2 is charge of 2, r is distance between the two.
 
        
             
        
        
        
Answer:
The magnitude of each charge is 
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N. 
We need to calculate the magnitude of each charge
Using formula of force

Where, q = charge
r = separation
Put the value into the formula




Hence, The magnitude of each charge is 
 
        
             
        
        
        
Answer:
Force, F = 16814.95 N
Explanation:
It is given that,
Mass of space station, m = 2010 kg
Altitude, 
Mass of earth, 
Mean radius of earth, 
Magnitude of force is given by :

R = r + d


F = 16814.95 N
So, the force between the space station and the Earth is 16814.95 N. Hence, this is the required solution.
 
        
             
        
        
        
To solve this problem we need to use the concepts related to fluid density. Since we need to know a height point of two different liquids, their pressures must be equal, so


Where,
 Density
Density
g = Gravitational acceleration
h = Height
Our values are given as,


 Standard mercury pressure at 1atm, the barometer height is 760.2mm.
 Standard mercury pressure at 1atm, the barometer height is 760.2mm. 
Replacing we have,


Therefore the tall of the barometer would be 1033.87 (Inconvenient compared with the Mercury Barometer)